If LOVE is a square with LO = 2x + 3 and OV = 9, what is the value of x?

Mathematics

2 answers:

velikii [3]2 years ago

4 0

Answer:

Step-by-step explanation:

2x+3=9

You have to get rid of the 3 and the operation that is happening between the 2x and 3 is addition so you must do the opposite which is subtract .

2x+3-3=9-3

Cross out the 3's . What you do to one side do it to the other side .So subtract 3 from both sides .

2x÷2=6÷2

Now to get rid of the 2 you divide because the operation that is happening between the 2 and x is multiplication.And what u do to one side do it to the other . So

x= 3

Hope this helps and sorry if you don't under the explanation

anzhelika [568]2 years ago

3 0

Step-by-step explanation:

LO = 2x + 3 and OV = 9,

9=2x+3

9-3=2x

6=2x

6/2=x

x=3

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