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3 years ago

An event has a probability of 1/2. How would you best describe the likelihood of this event? (Hint: Change it to a decimal)

Mathematics

1 answer:

noname [10]3 years ago

7 0

Answer:

Equally Likely

Step-by-step explanation:

The answer is equally likely because equally likely events have the same probability of happening as another event.

For example, a fair coin.

It has a 1/2 chance of beng tails, and 1/2 chance of being heads, meaning that both tails and heads are Equally Likely to land.

Hope this helps!

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The united states uses 24℅ of the world's supply energy what fraction of the world's energy is this ?

Mice21 [21]

24% = 24/100 = 12/50 = 6/25

24% is 6/25 fraction of world's energy.

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3 years ago

The temperature in the ice rink must stay below 50° F. This morning the temperature was 68°F. The ice rink runs a cooling device

german

The answer is h > 4.
Explanation: 68- 18=50
18/4=4.5. It is asking for below 50, and it had to cool for over 4 hours, which is >. I hope this helps. Please give me Brainliest.

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3 years ago

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Matthew wants to save up to buy a new PS5 whenever it comes out. He

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Answer:

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Step-by-step explanation:

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3 years ago

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30% of number A is the same as 40% of number B. what could A and B ? <br><br>

Sunny_sXe [5.5K]

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Answer:

A = 4, B = 3

Step-by-step explanation:

You require that ...

0.30 × A = 0.40 × B

Then ...

B = (3/4)A . . . . . divide by 0.40

Any pair of numbers that satisfies this equation will be possible values of A and B. One such pair is (A, B) = (4, 3).

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3 years ago

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A 90 percent confidence interval is to be created to estimate the proportion of television viewers in a certain area who favor m

Dominik [7]

Answer:

This means that the first interval, with 9000 viewers, is 3 times as narrower as the second interval, with 1000 viewers.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The width of the interval is:

$W = 2z\sqrt{\frac{\pi(1-\pi)}{n}}$

In this sample:

Two 90% intervals, with different lenghts. So both have the same values for z an $\pi$

Interval A:

9000 viewers.

So the width is

$W_{A} = 2z\sqrt{\frac{\pi(1-\pi)}{9000}}$

Interval B:

100 viewers

So the width is

$W_{B} = 2z\sqrt{\frac{\pi(1-\pi)}{1000}}$

Relationship between the widths:

$R = \frac{W_{A}}{W_{B}} = \frac{2z\sqrt{\frac{\pi(1-\pi)}{9000}}}{2z\sqrt{\frac{\pi(1-\pi)}{1000}}} = \frac{\sqrt{1000}}{\sqrt{9000}} = \frac{\sqrt{1}}{\sqrt{9}} = \frac{1}{3}$

This means that the first interval, with 9000 viewers, is 3 times as narrower as the second interval, with 1000 viewers.

8 0

3 years ago