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2 years ago

5

What is the surface area of the cylinder with height 4 in and radius 5 in? Round your answer to the nearest thousandth.

2 answers:

olasank [31]2 years ago

8 0

Answer:

$\fbox{Surface area of cylinder = 282.6 sq. in.}$

Step-by-step explanation:

Given:

Shape of object = cylinder

height of cylinder= 4 inches

radius of cylinder= 5 inches

To find:

surface area of cylinder = ?

Solution:

we know that,

$surface \: area \: of \: cylinder =2\pi{rh} + 2\pi {r}^{2}\\Substituting \:the \:constant\: (π =3.14)\\and \:given\: data,\\2\pi{rh} + 2\pi {r}^{2} \: =\\ 2×3.14×5×4+2×3.14× {5}^{2} \\2\pi{rh} + 2\pi {r}^{2} = 125.6 + 157 \\ 2\pi{rh} + 2\pi {r}^{2} = 282.6\\ \fbox{Surface area of cylinder = 282.6 sq. in.}$ [/tex]

<em><u>THANKS FOR JOINING BRAINLY COMMUNITY!</u></em>

MissTica2 years ago

4 0

Answer:

282.74

Step-by-step explanation:

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3 years ago

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Step-by-step explanation:

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3 years ago

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3 years ago

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Answer:

<u>______________________________________________________</u>

<u>TRIGONOMETRY IDENTITIES TO BE USED IN THE QUESTION :-</u>

For any right angled triangle with one angle α ,

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<u>SOME GENERAL TRIGNOMETRIC FORMULAS :-</u>

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<u>______________________________________________________</u>

Now , lets come to the question.

In a right angled triangle , let one angle be α (in place of theta) .

So , lets solve L.H.S.

$\cos (90 - \alpha ) \times cosec(90 - \alpha )$

$=> sin\alpha \times \sec\alpha$

$=> \sin\alpha \times \frac{1}{\cos\alpha }$

$=> \frac{\sin\alpha }{\cos\alpha }$

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∴ L.H.S. = R.H.S. (Proved)

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