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shusha [124]
3 years ago
9

PLS HELP ASAP...A triangle has side lengths of (10m-5) centimeters, (6m-2) centimeters, and (8n+4) centimeters. Which expression

represents the perimeter, in centimeters, of the triangle?
1. 12n+16m−7
2. 16m+8n−3
3. 12n+5m+4
4. 12n+9m
Mathematics
2 answers:
marshall27 [118]3 years ago
4 0

Answer:

12n+5m+4

Step-by-step explanation:

jek_recluse [69]3 years ago
4 0

Answer:

perimeter = 10m - 5 + 6m - 2 + 8n + 4

                = 16m -7 + 8n + 4

                 16m + 8n -3

option 2

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Answer:

13.73 sq mm

Step-by-step explanation:

Area of Square - Area of Circle = Area of Shaded Region

if radius of circle is 4 then diameter is 8

the diameter is the same as the length of each side of the square

so area of square = 8² or 64

Area of Circle = 16π

64 - 16π ≈ 13.73

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What number divided by 3 give me five
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It is 15 because 5 times 3 is 15
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A line has a slope of 1/2 and run =50. What is the rise
Svetllana [295]

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Answer:

CI=P*(1 + R/100)^18

A=(CI + P) = P(1+R/100)^18

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A/P=(100+R/100)^18

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3 0
3 years ago
Determine the measure of each segment then indicate whether the statements are true or false
kupik [55]

Answer:

d_{AB}\ne d_{JK}

d_{AB}\ne \:d_{GH}

d_{GH}\ne \:d_{JK}

Therefore,

Option (A) is false

Option (B) is false

Option (C) is false

Step-by-step explanation:

Considering the graph

Given the vertices of the segment AB

  • A(-4, 4)
  • B(2, 5)

Finding the length of AB using the formula

d_{AB}\:=\:\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}

        =\sqrt{\left(2-\left(-4\right)\right)^2+\left(5-4\right)^2}

         =\sqrt{\left(2+4\right)^2+\left(5-4\right)^2}

         =\sqrt{6^2+1}

         =\sqrt{36+1}

        =\sqrt{37}

d_{AB}\:=\sqrt{37}

d_{AB}=6.08 units        

Given the vertices of the segment JK

  • J(2, 2)
  • K(7, 2)

From the graph, it is clear that the length of JK = 5 units

so

d_{JK}=5 units

Given the vertices of the segment GH

  • G(-5, -2)
  • H(-2, -2)

Finding the length of GH using the formula

d_{GH}\:=\:\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}

         =\sqrt{\left(-2-\left(-5\right)\right)^2+\left(-2-\left(-2\right)\right)^2}

          =\sqrt{\left(5-2\right)^2+\left(2-2\right)^2}

          =\sqrt{3^2+0}

           =\sqrt{3^2}

\mathrm{Apply\:radical\:rule\:}\sqrt[n]{a^n}=a,\:\quad \mathrm{\:assuming\:}a\ge 0

d_{GH}\:=\:3 units

Thus, from the calculations, it is clear that:

d_{AB}=6.08  

d_{JK}=5

d_{GH}\:=\:3

Thus,

d_{AB}\ne d_{JK}

d_{AB}\ne \:d_{GH}

d_{GH}\ne \:d_{JK}

Therefore,

Option (A) is false

Option (B) is false

Option (C) is false

8 0
2 years ago
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