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elixir [45]
3 years ago
8

Two positive consecutive numbers are represented by x and x+1. If four is added to the first

Mathematics
2 answers:
Naya [18.7K]3 years ago
8 0

Step-by-step explanation:

<h3> new numbers are x+4 and x-1</h3>

so, x+4/x-1=11/16

16x+64=11x-11

16x-11x=-11-64

5x=-75

x = -15

also, x+1 = -14

Eduardwww [97]3 years ago
8 0

x =first number

x+1 = second number

(x) + 4 = x + 4 = 1 ^ new number [first number + 4]

(x + 1) -2 = x - 1 = 2 ^ new number [second number - 2]

\frac{x+4}{x-1}=\frac{11}{16}

now, we resolve it:

\frac{16(x+4)-11(x-1)}{16(x-1)}=0

\frac{16x+64-11x+11}{16x-16}=0

\frac{5x+75}{16x-16}=0

we eliminate the denominator and do c.e.: 16x - 16 ≠ 0; 16x ≠ 16; x ≠ 1

5x + 75 = 0

x = - 15

so x + 1 = - 14

But what you ask are two <u>positive</u> numbers! Are you sure that you write correctly the question? Thank you

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3 years ago
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Dexter has four different coins in his pocket. He randomly selects a coin from his pocket, replaces it, and selects another coin
skad [1K]

Answer:

Step-by-step explanation:

So what is the probability of the selecting the first coin? There are total of 4 different coins, so the probability of getting a dime is 1 out of 4, then he replace it, then again the probability stays the same, he still has 1 out 4 chance of getting a dime. So then it's just 1/4*1/4=1/16 :)

4 0
3 years ago
The probability that a certain hockey team will win any given game is 0.3723 based on their 13 year win history of 385 wins out
Whitepunk [10]

Answer:

0.1505 = 15.05% probability that the hockey team wins 6 games in November

Step-by-step explanation:

For each game, there are only two possible outcomes. Either the team wins, or it does not. The probability of winning a game is independent of winning other games. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

The probability that a certain hockey team will win any given game is 0.3723

So p = 0.3723

12 games in November

So n = 12

What is the probability that the hockey team wins 6 games in November?

This is P(X = 6)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 6) = C_{12,6}.(0.3723)^{6}.(1-0.3723)^{6} = 0.1505

0.1505 = 15.05% probability that the hockey team wins 6 games in November

4 0
3 years ago
Coach Evans recorded the height, in inches of each player on his team. The results are shown.
never [62]

Answer:

3

Step-by-step explanation:

3 0
3 years ago
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timurjin [86]
The giraffe (using the ruler) is 11 cm.

1 cm : 50 cm

Multiply both sides by 11.

11 cm : 550 cm 

There are 0.01 meters in 1 centimeter.

Multiply 550 cm by 0.01.

(550)(0.01) = 5.5

The giraffe's real length is 5.5 meters.
5 0
3 years ago
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