Question

Two positive consecutive numbers are represented by x and x+1. If four is added to the first

Answer 1

Step-by-step explanation:

new numbers are x+4 and x-1

so, x+4/x-1=11/16

16x+64=11x-11

16x-11x=-11-64

5x=-75

x = -15

also, x+1 = -14

Answer 2

x =first number

x+1 = second number

(x) + 4 = x + 4 = 1 ^ new number [first number + 4]

(x + 1) -2 = x - 1 = 2 ^ new number [second number - 2]

$\frac{x+4}{x-1}=\frac{11}{16}$

now, we resolve it:

$\frac{16(x+4)-11(x-1)}{16(x-1)}=0$

$\frac{16x+64-11x+11}{16x-16}=0$

$\frac{5x+75}{16x-16}=0$

we eliminate the denominator and do c.e.: 16x - 16 ≠ 0; 16x ≠ 16; x ≠ 1

5x + 75 = 0

x = - 15

so x + 1 = - 14

But what you ask are two positive numbers! Are you sure that you write correctly the question? Thank you