So using a calculator this question is really easy 125,000x 1.35 ^10 =.
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Answer:
The ball shall keep rising tills its velocity becomes zero. Let it rise to a height h feet from point of projection.
Step-by-step explanation:
Let us take the point of projection of the ball as origin of the coordinate system, the upward direction as positive and down direction as negative.
Initial velocity u with which the ball is projected upwards = + 120 ft/s
Uniform acceleration a acting on the ball is to acceleration due to gravity = - 32 ft/s²
The ball shall keep rising tills its velocity becomes zero. Let it rise to a height h feet from point of projection.
Using the formula:
v² - u² = 2 a h,
where
u = initial velocity of the ball = +120 ft/s
v = final velocity of the ball at the highest point = 0 ft/s
a = uniform acceleration acting on the ball = -32 ft/s²
h = height attained
Substituting the values we get;
0² - 120² = 2 × (- 32) h
=> h = 120²/2 × 32 = 225 feet
The height of the ball from the ground at its highest point = 225 feet + 12 feet = 237 feet.
Answer:
Area = pi X r^2 = pi x (1)^2 = 3.14 x 1 = 3.14
Step-by-step explanation:
Answer:
Solution one is correct and solution 2 and 3 are incorrect
Step-by-step explanation:
You simply make an equation because for vertical angles 2 angles that are across from each other have the same value (in this case 2x+30 and 5x-36.)
The equation: 2x+30=5x-36---->3x=66----> x=22
Solution 1 is correct.
Hope this helped!
