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fredd [130]
3 years ago
6

Joel is using a recipe to make cookies for a club bake sale.

Mathematics
2 answers:
olasank [31]3 years ago
6 0

Answer:

3/4 cups → 1 batch

x cups    → 2 batches

x = 2(3/4) = 6/4 = 1 1/2 cups

 

3/4 cups → 1 batch

y cups → 9 batches

y = 9(3/4) = 6 3/4 cups

Step-by-step explanation:

AleksAgata [21]3 years ago
4 0

Answer:

9 batches

Step-by-step explanation:

Number of batches of cookies = Total sugar ÷ Sugar need for each batch

        = 6 ÷ (2/3)

        = 6 * \frac{3}{2}\\\\= 3*3\\= 9

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Sam buys a DVD player for $55. 95 and it is on sale for 40% off regular price. How much money will same save
Lelu [443]

Answer:

$ 22.38

Step-by-step explanation:

If the pre-sale price is $ 55.95

 40 % of this would be  .4 * 55.95 =  $ 22.38

6 0
2 years ago
In ΔDEF, the measure of ∠F=90°, the measure of ∠D=66°, and EF = 32 feet. Find the length of FD to the nearest tenth of a foot.
Butoxors [25]

Answer:

14.2 ft

Step-by-step explanation:

tan 66° = 32/ FD

FD = 32 / tan 66° = 32 / 2.246 = 14.2

7 0
3 years ago
Find the area of the circle. Round your answer to the nearest hundredth. 15in
jekas [21]
Answer is 47.25

BRAINLIST?
4 0
3 years ago
Please help with this?
frez [133]

7p3 = 210
8 0
3 years ago
You throw a ball up and its height h can be tracked using the equation h=2x^2-12x+20.
postnew [5]

<em><u>This problem seems to be wrong because no minimum point was found and no point of landing exists</u></em>

Answer:

1) There is no maximum height

2) The ball will never land

Step-by-step explanation:

<u>Derivatives</u>

Sometimes we need to find the maximum or minimum value of a function in a given interval. The derivative is a very handy tool for this task. We only have to compute the first derivative f' and have it equal to 0. That will give us the critical points.

Then, compute the second derivative f'' and evaluate the critical points in there. The criteria establish that

If f''(a) is positive, then x=a is a minimum

If f''(a) is negative, then x=a is a maximum

1)

The function provided in the question is

h(x)=2x^2-12x+20

Let's find the first derivative

h'(x)=4x-12

solving h'=0:

4x-12=0

x=3

Computing h''

h''(x)=4

It means that no matter the value of x, the second derivative is always positive, so x=3 is a minimum. The function doesn't have a local maximum or the ball will never reach a maximum height

2)

To find when will the ball land, we set h=0

2x^2-12x+20=0

Simplifying by 2

x^2-6x+10=0

Completing squares

x^2-6x+9+10-9=0

Factoring and rearranging

(x-3)^2=-1

There is no real value of x to solve the above equation, so the ball will never land.

This problem seems to be wrong because no minimum point was found and no point of landing exists

3 0
3 years ago
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