In this situation triangle BOC is inscribed in the circle. Length of BC is 10,91, length of BO is 5 (radius) and length of CO is 5 (radius).
we need to know theorem of sines:
<span>(a.)
Let's say α is the angle that subtends from the top of the screen to horizontal eye-level.
Let β be the angle that subtends from the bottom of the screen to horizontal eye-level.
tanα = (22 + 10 - 4) / x = 28/x
α = arctan(28/x)
tanβ = (10 - 4) / x = 6/x
β = arctan(6/x)
Ɵ = α - β
Ɵ = arctan(28/x) - arctan(6/x)
(b.)
tanƟ = tan(α - β) = (tanα - tanβ) / (1 + tanα tanβ)
tanƟ = (28/x - 6/x) / [1 + (28/x)(6/x)]
tanƟ = (22/x) / [1 + (168/x²)]
tanƟ = 22x / (x² + 168)
Ɵ = arctan[22x / (x² + 168)]</span>
D because the shaded region has one side and subtract by pie and substitute to get this answer.
Answer:
8÷(x+3)
Step-by-step explanation:
it doesnt specify what number you add with 3 so you substitute it with a variable such as x.
The sum is adding so x +3 and then divide by 8
Answer:
29.9 cm
Step-by-step explanation:
