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2 years ago

11

I NEED HELP ASAP QUESTION BELOW

1 answer:

Gekata [30.6K]2 years ago

3 0

Answer:

Circumference ≈ 50.27

Area ≈ 201.06

Step-by-step explanation:

The circumference of a circle is $2\pi r$ while the area of the circle $\pi r^{2}$

Since the diameter is the radius multiplied by 2, the radius of the circle is 8. So substituting 8 for r, the circumference is 2 × $\pi$ × 8, which is approximately 50.27 (rounded to the nearest hundredth) and the area of the circle would be $\pi$ × 8². 8² is 64 so 64 times pi is approximately 201.06 (rounded to the nearest hundredth)

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Nicole got a prepaid debit card with $25 on it. For her first purchase with the card, she bought some bulk ribbon at a craft sto

vagabundo [1.1K]

Answer:

34 yards of ribbon

Step-by-step explanation:

If you will subtract the $17.52 to $25 you will get 7.48 then 7.48 divide to .22 you will get 34 as the answer

3 0

3 years ago

Can someone help. pls

Elan Coil [88]

Answer: 5

Step-by-step explanation:

Pythagorean Theorem = a^2 + b^2 = c^2 (hypotenuse)

the square root of 4^2 + 3^2 = c

c = 5

3 0

2 years ago

Prove that a triangle with the sides a - 1 cm to root under a

vivado [14]

Question is Incomplete, Complete question is given below.

Prove that a triangle with the sides (a − 1) cm, 2√a cm and (a + 1) cm is a right angled triangle.

Answer:

∆ABC is right angled triangle with right angle at B.

Step-by-step explanation:

Given : Triangle having sides (a - 1) cm, 2√a and (a + 1) cm.

We need to prove that triangle is the right angled triangle.

Let the triangle be denoted by Δ ABC with side as;

AB = (a - 1) cm

BC = (2√ a) cm

CA = (a + 1) cm

Hence,

${AB}^2 = (a -1)^2$

Now We know that

$(a- b)^2 = a^2+b^2 - 2ab$

So;

${AB}^2= a^2 + 1^2 -2\times a \times1$

${AB}^2 = a^2 + 1 -2a$

Now;

${BC}^2 = (2\sqrt{a})^2= 4a$

Also;

${CA}^2 = (a + 1)^2$

Now We know that

$(a+ b)^2 = a^2+b^2 + 2ab$

${CA}^2= a^2 + 1^2 +2\times a \times1$

${CA}^2 = a^2 + 1 +2a$

${CA}^2 = AB^2 + BC^2$

[By Pythagoras theorem]

$a^2 + 1 +2a = a^2 + 1 - 2a + 4a\\\\a^2 + 1 +2a= a^2 + 1 +2a$

Hence, ${CA}^2 = AB^2 + BC^2$

Now In right angled triangle the sum of square of two sides of triangle is equal to square of the third side.

This proves that ∆ABC is right angled triangle with right angle at B.

4 0

3 years ago

Congruent definition

Yuliya22 [10]

When they are the exact same, like carbon copies

3 0

2 years ago

Read 2 more answers

Find the missing side of the triangle

Yuri [45]

Answer:

x = 15

Step-by-step explanation:

Pytago: a^2 + b^2 = c^2

x = $\sqrt{25^{2} -20^{2} }$ = 15

6 0

3 years ago