For a probability distribution to be represented, it is needed that P(X = 0) + P(X = 1) = 0.44. Hence one possible example is:
<h3>What is needed for a discrete random variable to represent a probability distribution?</h3>
The sum of all the probabilities must be of 1, hence:
P(X = 0) + P(X = 1) + P(X = 3) + P(X = 4) + P(X = 5) = 1.
Then, considering the table:
P(X = 0) + P(X = 1) + 0.15 + 0.17 + 0.24 = 1
P(X = 0) + P(X = 1) + 0.56 = 1
P(X = 0) + P(X = 1) = 0.44.
Hence one possible example is:
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Answer:
given a triangle with sides A, B and C the sum of the lengths of any two sides of a triangle must be greater than the third side:
1. A+B>C
2. B+C>A
3. A+C>B
Thus given two sides of A=9 and B=12 C can be:
12−9<C<12+9
C range 5<C<11
Hope this helps you!
4 more
If it takes 6 miles to get there,(4+2) And then 6+2 is how much she walked. And 4 is how much she rode. 8-4=4
Answer:
15 people
Step-by-step explanation:
35 divided by 7 is 5. Thus 3/7 are 5 times 3.