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3 years ago

Please help me!! there's three questions (equivalent fractions)

Mathematics

1 answer:

iren2701 [21]3 years ago

7 0

Answer:

Hello!

1st problem: 5

2nd problem: 1

3rd problem: 12

What you do with these is cross multiply I believe so... for the top 20 × 8 = 160 now we can just divide that by 32 for the missing blank so...

160 ÷ 32 = 5 so 5 is the first answer the next one we do 4 × 12 = 48 14 ÷ 48 = 1 so the missing blank is 1 and for the last problem 9 × 4 = 36 36 ÷ 3 = 12 so that last missing blank is 12 HOPE THIS HELPS!

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Describe 2 ways that an exterior angle of a triangle is related to one or more or the interior angles

shtirl [24]

The 2 angles at a vertex are supplementary (one interior and one exterior) the exterior angle is = the the sum of the 2 remote interior angles..

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3 years ago

80 POINTS ANSWER QUICKLY (and correctly)

andrew11 [14]

Answer:

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2 years ago

If 1st and 4tg terms of G.p are 500 and 32 respectively it's second term is ?

bixtya [17]

Answer:

$T_{2} = 200$

Step-by-step explanation:

Given

Geometry Progression

$T_1 = 500$

$T_4 = 32$

Required

Calculate the second term

First, we need to write out the formula to calculate the nth term of a GP

$T_n = ar^{n-1}$

For first term: Tn = 500 and n = 1

$500 = ar^{1-1}$

$500 = ar^{0}$

$500 = a$

$a = 500$

For fought term: Tn = 32 and n = 4

$32 = ar^{4-1}$

$32 = ar^3$

Substitute 500 for a

$32 = 500 * r^3$

Make r^3 the subject

$r^3 = \frac{32}{500}$

$r^3 = 0.064$

Take cube roots

$\sqrt[3]{r^3} = \sqrt[3]{0.064}$

$r = \sqrt[3]{0.064}$

$r = 0.4$

Using: $T_n = ar^{n-1}$

$n = 2$ $r = 0.4$ and $a = 500$

$T_{2} = 500 * 0.4^{2-1}$

$T_{2} = 500 * 0.4^1$

$T_{2} = 500 * 0.4$

$T_{2} = 200$

<em>Hence, the second term is 200</em>

5 0

3 years ago

So, the area <br> Find the area of the figure of

ch4aika [34]

Answer:

The area of the figure is 117m²

Step-by-step explanation:

In this problem, you have two shapes. One shape is a rectangle. The other shape is a triangle.

Area of a rectangle = b*h = 9*7 = 63

Area of a triangle = $\frac{1}{2}$ (b*h) =

Since there are two triangles, you will multiply the area of the one triangle in the figure by 2.

27*2 = 54

Now, you add up the areas!

54 + 63 = 117

So, the area of the figure is 117m²

7 0

4 years ago

Read 2 more answers

How many different ordered pairs (x, y) are there suchthat x is an even integer, where 4 <= x <= 10, and y isan integer, w

german

Correct option is C. There are 20 ordered pairs.

Given that ordered pairs (x,y)

such that x is even integer where 4≤x≤10 and y is an integer.

where 4<y<10.

Then even integer 4≤x≤10 are four i:e

4,6,8,10

And integer 4<y<10 are five i:e

5,6,7,8,9

Then ordered pair are = 4×5=20

<h3>What are ordered pairs?</h3>

An ordered pair is a composition of the x coordinate (abscissa) and the y coordinate (ordinate), having two values written in a fixed order within parentheses. It helps to locate a point on the Cartesian plane for better visual comprehension. The numeric values in an ordered pair can be integers or fractions.

To learn more about ordered pairs from given link

brainly.com/question/1528681

#SPJ4

7 0

2 years ago

Please help me!! there's three questions (equivalent fractions)​

Please help me!! there's three questions (equivalent fractions)