Answer:
∠ BAC = 80°
Step-by-step explanation:
The sum of the interior angles of quadrilateral ACDB = 360°
DB and DC are tangents to the circle, thus
∠ DBA = ∠ ACD = 90° ( angle between tangent/ circle at point of contact )
Thus
∠ BAC + 90° + 90° + 100° = 360°
∠ BAC + 280° = 360° ( subtract 280° from both sides )
∠ BAC = 80°
Answer:
3520
Step-by-step explanation:
33-11=22
40 times 22=880
880 times 4=3520
Answer:
3x+2y=15--------(1)
4x+2y=20--------(2)
then, 2y=15-3x------(3)
putting value of 2y in equation (2)
4x+15-3x=20
x=5
then after , putting value of x in eq(3)
y=(15-15)/2
y=0
