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Temka [501]
2 years ago
8

I need help finding our the perimeter

Mathematics
1 answer:
barxatty [35]2 years ago
3 0

Answer:

11x + 10y - 2w

Step-by-step explanation:

Hello!

To solve for the perimeter, we add up the like terms.

What are like terms?

Like terms are terms with the same variable and degree. 4x and 5y are NOT like terms because the variable is not the same. However, 4x and 3x are like terms, as adding them gives us 7x.

4x and 4x² are not like terms, because the degree of 4x is 1 (degree means the largest exponent), but the degree of 4x² is 2.

Solve for Perimeter:

Combine the like terms by adding them up.

  • Perimeter = (8x - 4w) + (3y + 2w) + (3x + 7y)
  • P = 8x - 4w + 3y + 2w + 3x + 7y
  • P = 8x + 3x + 3y + 7y - 4w + 2w
  • P = 11x + 10y - 2w

The perimeter is 11x + 10y - 2w

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The hypotenuse of a 45°-45°-90° triangle measures 128 cm. A right triangle is shown. The length of the hypotenuse is 128 centime
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Step-by-step explanation:

A 45-45-90 traingle is a special traingle.  Let's say one of the leg of the triangle is x. The other one is also x because of the isosocles triangle theorem.  Therefore, using the pytagorean theorem, you find that x^2+x^2=c^2.  2(x)^2=c^2.  You then square root both sides and get c= x√2.  

Therefore, the two legs are x and the hypotenuse is x√2.  x√2=128 because the question says that the hypotenuse is 128.  Solve for x by dividing both sides by √2.  X=128/√2.  You rationalize it by multiplying the numberator and denominator of the fraction by √2.  √2*√2= 2.

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3 years ago
Read 2 more answers
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