How do I create a radical equation with an extraneous solution quickly? How do I go the same for a radical equation with a non-e
1 answer:
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Answer:
Step-by-step explanation:
<u>Linear Combination Of Vectors </u>
One vector is a linear combination of
and
if there are two scalars
such as
In our case, all the vectors are given in but there are only two possible components for the linear combination. This indicates that only two conditions can be used to determine both scalars, and the other condition must be satisfied once the scalars are found.
We have
We set the equation
Multiplying both scalars by the vectors
Equating each coordinate, we get
Adding the first and the third equations:
Replacing in the first equation
We must test if those values make the second equation become an identity
The second equation complies with the values of and
, so the solution is
The spinner is divided into four equal sections: 2, 4, 7, 9. This represents 4 possibilities
If the spinner is spun twice, the sample space is:
For product less than 30, the number of outcomes is shown below:
The number of outcomes that have a product less than 30 = 10
The sample space that shows possibilities of an odd number combination:
The number of outcomes that contains at least one odd number = 12
The number of outcomes that have a product less than 30 and contain at least one odd number is shown below. These outcomes are outcomes circled in both cases shown above,
The outcomes circled represents the number of outcomes that has a product less than 30 and contains at least one odd number
Answer: 6 (option B)
