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grin007 [14]
3 years ago
8

How do I create a radical equation with an extraneous solution quickly? How do I go the same for a radical equation with a non-e

xtraneous solution?
Mathematics
1 answer:
Step2247 [10]3 years ago
5 0

Answer:

why r u wafflin

Step-by-step explanation:

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Find an expression which represents the sum of (-3x-4y)(−3x−4y) and (x+3y)(x+3y) in simplest terms
ella [17]

Answer:

The sum of (−3x−4y) and (x+3y) in simplest terms will be:

\left(-3x-4y\right)+\left(x+3y\right)=-2x-y

Step-by-step explanation:

Given

  • (−3x−4y)
  • (x+3y)

Finding the sum of (−3x−4y) and (x+3y)

\left(-3x-4y\right)+\left(x+3y\right)

=-3x-4y+x+3y

=-3x+x-4y+3y

=-2x-4y+3y

=-2x-y

Therefore, the sum of (−3x−4y) and (x+3y) in simplest terms will be:

\left(-3x-4y\right)+\left(x+3y\right)=-2x-y

8 0
3 years ago
Rewrite 2 5/8 with a denominator of 24
gladu [14]

Answer:

63/24

Step-by-step explanation:

First you change the whole 2 to have a fraction of 48/24.

Next you have change 5/8 so its denominator has a 24. So you multiple the 8 by 3 to get 5/24. But then you have to multiply the 5 by 3 also so it is still the same fraction just bigger and you get 15/24. Now add the 15/24 with 48/24 to get 63/24.

Hope this helps!

3 0
3 years ago
Identify the four terms of the treaty of Guadalupe Hidalgo
butalik [34]

Answer:

Treaty of Guadalupe Hidalgo (1848) This treaty, signed on February 2, 1848, ended the war between the United States and Mexico. By its terms, Mexico ceded 55 percent of its territory, including parts of present-day Arizona, California, New Mexico, Texas, Colorado, Nevada, and Utah, to the United States.

Step-by-step explanation:

5 0
4 years ago
The given matrix is the augmented matrix for a linear system. Use technology to perform the row operations needed to transform t
shtirl [24]

Answer:

x_{1} = \frac{176}{127} + \frac{71}{127}x_{4}\\\\ x_{2} = \frac{284}{127} + \frac{131}{254}x_{4}\\\\x_{3} = \frac{845}{127} + \frac{663}{254}x_{4}\\

Step-by-step explanation:

As the given Augmented matrix is

\left[\begin{array}{ccccc}9&-2&0&-4&:8\\0&7&-1&-1&:9\\8&12&-6&5&:-2\end{array}\right]

Step 1 :

r_{1}↔r_{1} - r_{2}

\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&7&-1&-1&:9\\8&12&-6&5&:-2\end{array}\right]

Step 2 :

r_{3}↔r_{3} - 8r_{1}

\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&7&-1&-1&:9\\0&124&-54&77&:-82\end{array}\right]

Step 3 :

r_{2}↔\frac{r_{2}}{7}

\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&124&-54&77&:-82\end{array}\right]

Step 4 :

r_{1}↔r_{1} + 14r_{2} , r_{3}↔r_{3} - 124r_{2}

\left[\begin{array}{ccccc}1&0&4&-11&:-8\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&0&- \frac{254}{7} &\frac{663}{7} &:-\frac{1690}{7} \end{array}\right]

Step 5 :

r_{3}↔\frac{r_{3}. 7}{254}

\left[\begin{array}{ccccc}1&0&4&-11&:-8\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&0&1&-\frac{663}{254} &:-\frac{1690}{254} \end{array}\right]

Step 6 :

r_{1}↔r_{1} - 4r_{3} , r_{2}↔r_{2} + \frac{1}{7} r_{3}

\left[\begin{array}{ccccc}1&0&0&-\frac{71}{127} &:\frac{176}{127} \\0&1&0&-\frac{131}{254} &:\frac{284}{127} \\0&0&1&-\frac{663}{254} &:\frac{845}{127} \end{array}\right]

∴ we get

x_{1} = \frac{176}{127} + \frac{71}{127}x_{4}\\\\ x_{2} = \frac{284}{127} + \frac{131}{254}x_{4}\\\\x_{3} = \frac{845}{127} + \frac{663}{254}x_{4}\\

6 0
3 years ago
What are the domain and range of the function f(x)=sqrtx+2-3
svet-max [94.6K]
The answer is choice 3.
6 0
4 years ago
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