Answer:
6(x + 2)^2 + 8x + 2 + 1 = 0
Step-by-step explanation:
A quadratic equation has the variable with the highest power of 2
6(x + 2)^2 + 8x + 2 + 1 = 0 when foiled out it has the highest power of 2
6x4 + 7x2 – 3 = 0 power of 4
5x6 + x4 + 12 = 0 power of 6
x9 + x3 – 10 = 0 power of 9
Answer:
Area of the remaining triangle with the villager is 1243.13 m²
Step-by-step explanation:
Triangle ABC is the triangular plot of a villager shown in the figure attached.
Sarpanch requested the villager to donate land which is 6 m wide and along the side AC which measures 132.8m.
Other sides of the plot has been given as AB = 50m and BC = 123 m.
Now area of this land before donation = 
= 
= 3075 square meter
After donation of the land the triangle formed is ΔDBE.
In ΔABC,

tan(∠ABC) = 
= 0.4065
∠ABC = 
= 22.12°
In ΔEFC,
tanC = 
0.4065 = 
CF = 
CF = 14.76 m
Since DE = AC - (CF + AG)
= 132.8 - (2×14.76)
= 132.8 - 29.52
= 102.48 m
Now in ΔDBE,
sin(∠DEB) = 
sin(22.12) = 
DB = 102.48×0.3765
= 38.59 m
Similarly, cos(22.12) = 
0.9264 = 
BE = 102.48×0.9264
= 94.94m
Now area of ΔDBE = 
= 
= 1831.87 square meter
Area of remaining triangle with the villager = Area of ΔABC - Area of ΔDBE
= 3075 - 1831.87
= 1243.13 square meter
Answer:
ok I guess we should I am not good I am mad so yeah
Answer:
arc length = radius * angle in degrees * (PI / 180)
arc length = 6 * 160 * (PI/180)
arc length = PI * 960 / 180
arc length = PI * 5 + (60/180)
arc length = (16/3) * PI
Step-by-step explanation:
Answer:
The Answer to 17 1/3 x 8 is 138.67
There is not enough context to answer the second question.