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2 years ago

1/2+3/4+4/5 how to solve it please help me i'm waiting

Mathematics

1 answer:

likoan [24]2 years ago

7 0

Answer:

41/20

Step-by-step explanation:

or 2 1/20

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The color of any object depends upon which colors are reflected and absorbed. True or False?

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Answer:

true

Step-by-step explanation:

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3 years ago

Read 2 more answers

Jessica has an account with a credit union. Her account earns 2.4% simple interest yearly. Exactly a year and a half ago, she op

Dafna1 [17]

The basic equation for interest is the investment amount(x) times the time in years(y) times the percent of interest(z).

That makes the equation:

x·y·z= amount with interest.

Lets plug in the numbers:

$900 x 1.5 x 2.4%

Now turn the percent into a decimal:

2.4% ----> .024

Now the equation is:

$900 x 1.5 x .024

Now do the math:

$900 x 1.5 = 1350
1350 x .024 = 32.4
1350 + 32.4 = 1382.4

The final answer is $1382.40

Hope this helps!

6 0

3 years ago

If m(angle sign)1=34 then what is m(angle sign)4

sergejj [24]

The m (angle sign) for 4 is 38. I hope i helped.

4 0

3 years ago

F 216 1 36 O O O O no solution DONE

tester [92]

Answer:

join my kahoot

https://kahoot.it/challenge/09174317?challenge-id=67e37a3e-3175-473f-8bbe-bf5d0a6a5db5_1616009227053

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Step-by-step explanation:

4 0

3 years ago

ACTIVITY 2 (19) Mr Duma recently inherited a rectangular plot, part of the estate left by his late father. The plot with the fol

seraphim [82]

The sum of the lengths of three sides of the rectangle, gives the length

of the fencing, while one third of the rectangle area is for the pavement.

Responses:

Project A: The formula for the length of the fencing is, L = 4·x - 1

Project B: Length of the fancy wall = 2·x + 1

$Project \ C:Area \ of \ the \ paving = \underline{ \dfrac{2\cdot x^2 }{3} - \dfrac{x }{3} - \dfrac{1}{3}}$

<h3>Which method can be used to find the length and area of paving from the given equations?</h3>

Project A: Let QP and SR represent the longest sides of the rectangle, we have;

PQ = SR = 2·x + 1

Given parameters are;

Length of the rectangular plot = 2·x + 1

Width of the rectangular plot = x - 1

Vertices of the rectangular plot are; QPSR

Project A: Let QP and SR represent the longest sides of the rectangle, we have;

PQ = SR = 2·x + 1

Which gives;

SP = QR = x - 1

The length of the fencing, L = SP + PQ + QR = x - 1 + 2·x + 1 + x - 1 = 4·x - 1

The formula for the length of the fencing is, L = 4·x - 1

Project B: The front side is SR

Therefore;

Length of the fancy wall = 2·x + 1

Project C:

Area, A = Length × Width

Area of the plot, A = (2·x + 1) × (x - 1) = 2·x² - x - 1

$Area \ of \ the \ paving = \dfrac{1}{3} \times \left(2 \cdot x^2 - x - 1\right) = \underline{ \dfrac{2\cdot x^2 }{3} - \dfrac{x }{3} - \dfrac{1}{3}}$

Learn more about writing equations here:

brainly.com/question/24760633

6 0

2 years ago