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salantis [7]
2 years ago
10

First to answer correctly will be marked brainliest

Mathematics
1 answer:
kozerog [31]2 years ago
7 0

Answer:

Step-by-step explanation:

  • Binomial: 2 terms
  • Trinomial: 3 terms
  • Linear: a straight line
  • Quadratic: like a curved line

(3x + 2) - (x + 5)

1(3x + 2) - 1(x + 5)

3x + 2 - x - 5 <== combine like terms

3x - x + 2 - 5

2x - 3 <== final answer, linear binomial

(2x + 8) + (3x² - 2)

1(2x + 8) + 1(3x² - 2)

2x + 8 + 3x² - 2

3x² + 2x + 6 <== final answer, quadratic trinomial

(3x + 8) + (4x² - x)

1(3x + 8) + 1(4x² - x)

3x + 8 + 4x² - x

4x² + 2x + 8 <== final answer, quadratic trinomial

(x² + 5x minus (-) 2) + (8 minus (-) 5x)

(x² + 5x - 2)  + (8 - 5x)

1(x² + 5x - 2)  + 1(8 - 5x)

x² + 5x - 2 + 8 - 5x

x² + 6 <== final answer, quadratic binomial

(x² + 7x) - (x² + 5)

1(x² + 7x) - 1(x² + 5)

x² + 7x - x² - 5

7x - 5 <== final answer, linear binomial

Hope this helps!

You might be interested in
5 baseballs to 25 softballs in simplest form
sashaice [31]

Answer:

1/5

Step-by-step explanation:

5 baseballs to 25 softballs

=

1 baseballs to 5 softballs in simplest form

5 0
4 years ago
Read 2 more answers
Sums of a sequence: How many total gifts did my true love give to me during the entire 12 days of Christmas? Hint: Without any o
ale4655 [162]
<span> On the first day of Christmas,
my true love sent to me
A partridge in a pear tree. On the second day of Christmas,
my true love sent to me
Two turtle doves,
And a partridge in a pear tree. On the third day of Christmas,
my true love sent to me
Three French hens,
Two turtle doves,
And a partridge in a pear tree. </span>

The song continues, adding 4 calling birds on the 4th day, 5 golden rings on the 5th, and so on up to the 12th day, when 12 drummers add to the cacophony of assorted birds, pipers and lords leaping all over the place.

Notice that on each day there is one partridge (so I will have 12 partridges by the 12th day), and each day from the second day onwards there are 2 doves (so I will have 22 doves), and from the 3rd there are 3 hens (total of 30 hens), and so on.

So, how many presents are there altogether?

Partridges: 1 × 12 = 12

Doves: 2 × 11 = 22

Hens 3 × 10 = 30

Calling birds: 4 × 9 = 36

Golden rings: 5 × 8 = 40

Geese: 6 × 7 = 42

Swans: 7 × 6 = 42

Maids: 8 × 5 = 40

Ladies: 9 × 4 = 36

Lords: 10 × 3 = 30

Pipers: 11 × 2 = 22

Drummers: 12 × 1 = 12

Total = 364

We observe that we have the same number of partridges as drummers (12 of each); doves and pipers (22 of each); hens and lords (30 of each) and so on. So the easiest way to count our presents is to add up to the middle of the list and then double the result: (12 + 22 + 30 + 36 + 40 + 42) × 2 = 364.


3 0
3 years ago
Read 2 more answers
An urn contains 5 red, 6 blue, and 8 green balls. If a set of 3 balls is randomly selected, what is the probability that each of
monitta

Answer:

As a fraction, the answer is exactly 86/969

In decimal form, the answer is approximately 0.08875

=====================================================

Work Shown:

The assumption is that no replacements are made for each selection.

5 red, 6 blue, 8 green

5+6+8 = 19 total

A = P(3 red) = (5/19)*(4/18)*(3/17) = 10/969

B = P(3 blue) = (6/19)*(5/18)*(4/17) = 20/969

C = P(3 green) = (8/19)*(7/18)*(6/17) = 56/969

D = P(3 all same color)

D = A+B+C

D = 10/969 + 20/969 + 56/969

D = (10+20+56)/969

D = 86/969

D = 0.08875

6 0
3 years ago
What effect does replacing x with x + 2 have on the graph for the function f(x) ?
IrinaK [193]
The answer is A.

When replacing the variable 'x' by 'x + 2' the graph is shifted 2 units to the left. When we replace the variable, the function changes

from
f(x) = |x - 3| + 2

To
f(x) = |(x + 2) - 3| + 2
f(x) = |x - 1| + 2

And therefore the function is shifted 2 to the left.
3 0
3 years ago
Assume you have 4 fins, each with a mass of 8grams. what's the total weight of these 4 fines?
Kryger [21]
1 fin = 8 grams
4 fins = 4 x 8 = 24 grams total
3 0
3 years ago
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