First to answer correctly will be marked brainliest
1 answer:
Answer:
Step-by-step explanation:
- Binomial: 2 terms
- Trinomial: 3 terms
- Linear: a straight line
- Quadratic: like a curved line
(3x + 2) - (x + 5)
1(3x + 2) - 1(x + 5)
3x + 2 - x - 5 <== combine like terms
3x - x + 2 - 5
2x - 3 <== final answer, linear binomial
(2x + 8) + (3x² - 2)
1(2x + 8) + 1(3x² - 2)
2x + 8 + 3x² - 2
3x² + 2x + 6 <== final answer, quadratic trinomial
(3x + 8) + (4x² - x)
1(3x + 8) + 1(4x² - x)
3x + 8 + 4x² - x
4x² + 2x + 8 <== final answer, quadratic trinomial
(x² + 5x minus (-) 2) + (8 minus (-) 5x)
(x² + 5x - 2) + (8 - 5x)
1(x² + 5x - 2) + 1(8 - 5x)
x² + 5x - 2 + 8 - 5x
x² + 6 <== final answer, quadratic binomial
(x² + 7x) - (x² + 5)
1(x² + 7x) - 1(x² + 5)
x² + 7x - x² - 5
7x - 5 <== final answer, linear binomial
Hope this helps!
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Answer:
Area = 64
Step-by-step explanation:
area of a square =
side length = 8
= 64
I made a probability tree. Pls. see attachment.
Based on the probability tree I made, below are the probabilities
Probability of a student accepted at both Dartmouth and Harvard is:
50% x 40% = 20%
Probability of a student accepted at Dartmouth but not Harvard is:
50% x 60% = 30%
Probability of a student not accepted at Dartmouth but accepted in Harvard is:
50% x 20% = 10%
Probability of a student not accepted in both schools is:
50% x 80% = 40%
As you can see, these probabilities total 100%
Based on the probability tree I made, below are the probabilities
Probability of a student accepted at both Dartmouth and Harvard is:
50% x 40% = 20%
Probability of a student accepted at Dartmouth but not Harvard is:
50% x 60% = 30%
Probability of a student not accepted at Dartmouth but accepted in Harvard is:
50% x 20% = 10%
Probability of a student not accepted in both schools is:
50% x 80% = 40%
As you can see, these probabilities total 100%
Answer: points B (4,7) and I (9,3)
If the inequalities are
y > −2x + 10 and y> (½)x -2
Step-by-step explanation: If I interpreted the inequalities correctly, the attached graph shows them. It is possible that you meant y > 1/(2x-2) for the second inequality. If so, we start over!
You can test the values for all the points, but it appears that (4,7) and (9,3) both work.
The other coordinates appear to be outside the solution -- the dark-shaded area.
I hope this is your Brainliest answer. It was a lot of work!
