Answer:
'Substitute the slope and the coordinates of point P(-3,2) in y = mx + b and then solve for b in each equation'.
Step-by-step explanation:
Kiana wants to write equations in the form y = mx + b for the lines passing through point P that are parallel and perpendicular to line q.
This equation is in the slope-intercept form where m is the slope and b is the y-intercept.
First, she finds the slope of line q and the slope of line s to be – 2. Point P is located at (-3,2).
Therefore, the step that can be used to find the y-intercept is 'substitute the slope and the coordinates of point P(-3,2) in y = mx + b and then solve for b in each equation'. (Answer)
Using translation concepts, a stretch of a decay exponential function is given by:
<h3>What is a translation?</h3>
A translation is represented by a change in the function graph, according to operations such as multiplication or sum/subtraction in it's definition.
An exponential decay function is given by:
In which |b| < 1.
A stretch means that the function is <u>multiplied by a factor with absolute value greater than 1</u>, hence the function would be given by:
More can be learned about translation concepts at brainly.com/question/4521517
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Find the first perfect square that is larger than 12864. We can do this by taking the square root of 12864 finding the ceiling of that result and squaring it
which is
12996
Now find the difference between the next largest perfect square and the original number:
12996-12864
132
So 132 is the integer that needs to be added to 12864 to make it a perfect square.
Check:
Take the square root of 12864+132:
%:12864+132
114
So it’s a perfect square.
Answer:
83.33 cajas estándar de frambuesas y 51.67 cajas de lujo de frambuesas.
Step-by-step explanation:
Representemos el número de cajas como
A = caja estándar de frambuesas
B = caja de lujo de frambuesas
Caja estándar de frambuesas = $ 7 Caja de lujo de frambuesas = 10.
A + B = 135 ......... Ecuación 1
B = 135 - A
7A + 10B = 1100 ........... Ecuación 2
Sustituir
135 - A para B en la ecuación 2
7A + 10 (135 - A) = 1100
7A + 1350 -10A = 1100
7A - 10A = 1100-1350
-3A = - 250
A = 250/3
A = 83.33 cajas
Sustituye 83.33 por A en la ecuación 1
A + B = 135
83,33 + B = 135
B = 135 - 83.33 = 51.67 cajas
Por lo tanto, vendió,
83.33 cajas estándar de frambuesas y 51.67 cajas de lujo de frambuesas.
R=4 because 20-4 = 16 and 4 times 4 = 16
