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Levart [38]
2 years ago
7

Paige used 1 1/2 cups of flour and 1/4 cup of butter to make 12 muffins. How much flour and butter would palat

Mathematics
1 answer:
yanalaym [24]2 years ago
7 0

Answer:

D

Step-by-step explanation:

To turn the fraction of 1 1/2 to decimal would be : 1.50 add fifty percent because you have to add 6 to 12 and six is half, so you add half. Half of 150 is 75 so add them you get 225 and as a fraction, that's 2 1/4. Already you have the first part done. Since there is only one answer with 2 1/3 your answer has to be D.

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What is 18k + 30fk in like terms. Will give brainliest to correct answer.
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Answer:

6k(5f+3)

Step-by-step explanation:

18k+30fk

Factor out 6.

6(3k+5fk)

Consider 3k+5fk. Factor out k.

k(3+5f)

Rewrite the complete factored expression.

6k(5f+3)

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What's 19/30 x 12/16?
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19/40 as a fraction and decimal it is 0.475
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Miss Garner has 69 gold stickers. She wants to give the same number of stickers to each of her 15 students. If she gives away as
Hatshy [7]

Answer: 69/15=4 and remainder 9

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Sonji paid $25 for two scarves, which were different prices. When she got home she could not find the receipt. She remembered th
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x

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3 years ago
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Because not all airline passengers show up for their reserved seat, an airline sells 125 tickets for a flight that holds only 12
melamori03 [73]

Answer:

98.75% probability that every passenger who shows up can take the flight

Step-by-step explanation:

For each passenger who show up, there are only two possible outcomes. Either they can take the flight, or they do not. The probability of a passenger taking the flight is independent from other passenger. So the binomial probability distribution is used to solve this question.

However, we are working with a large sample. So i am going to aproximate this binomial distribution to the normal.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

The probability that a passenger does not show up is 0.10:

This means that the probability of showing up is 1-0.1 = 0.9. So p = 0.9

Because not all airline passengers show up for their reserved seat, an airline sells 125 tickets

This means that n = 125

Using the approximation:

\mu = E(X) = np = 125*0.9 = 112.5

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{125*0.9*0.1} = 3.354

(a) What is the probability that every passenger who shows up can take the flight

This is P(X \leq 120), so this is the pvalue of Z when X = 120.

Z = \frac{X - \mu}{\sigma}

Z = \frac{120 - 112.5}{3.354}

Z = 2.24

Z = 2.24 has a pvalue of 0.9875

98.75% probability that every passenger who shows up can take the flight

7 0
3 years ago
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