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nadezda [96]
3 years ago
6

Find a degree 3 polynomial with real coefficients having zeros 1 and 2-2i and a lead coefficient of 1. Write P in expanded form.

Be sure to write the full equation, including P(x)=.
Mathematics
1 answer:
amm18123 years ago
4 0

Answer:

Step-by-step explanation:

complex roots always occur in pairs.

roots are 1,2-2i,2+2i

P(x)=a(x-a)(x-b)(x-c)

P(x)=1(x-1)[x-(2-2i)][x-(2+2i)]

=1(x-1)[(x-2)+2i][(x-2)-2i]

=(x-1)[(x-2)²-(2i)²]

=(x-1)[(x-2)²-4i²]

=(x-1)[x²-4x+4-4(-1)]

=(x-1)[x²-4x+4+4]

=(x-1)[x²-4x+8]

=x³-4x²+8x-x²+4x-8

=x³-5x²+12x-8

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118° (10x+2)° solve for x and z
Ghella [55]

Answer:

Simplifying

10x + -2 = 118

Reorder the terms:

-2 + 10x = 118

Solving

-2 + 10x = 118

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '2' to each side of the equation.

-2 + 2 + 10x = 118 + 2

Combine like terms: -2 + 2 = 0

0 + 10x = 118 + 2

10x = 118 + 2

<em><u>Combine like terms: 118 + 2 = 120</u></em>

<em><u>Combine like terms: 118 + 2 = 12010x = 120</u></em>

<em><u>Combine like terms: 118 + 2 = 12010x = 120Divide each side by '10'.</u></em>

<em><u>Combine like terms: 118 + 2 = 12010x = 120Divide each side by '10'.x = 12</u></em>

<em><u>Combine like terms: 118 + 2 = 12010x = 120Divide each side by '10'.x = 12Simplifying</u></em>

<em><u>Combine like terms: 118 + 2 = 12010x = 120Divide each side by '10'.x = 12Simplifyingx = 12</u></em>

6 0
3 years ago
I need help with 1,2, and 3
Lelu [443]
1.
Lines a and b are parallel lines.
Line t is a transversal.
Corresponding angles are congruent.
Angle 1 is a corresponding angle to the 107-deg angle, so m<1 = 107.
Angles 1 and 2 are supplementary angles since they are a linear pair.
m<1 + m<2 = 180
m<2 = 180 - 107
m<2 = 73

2.
Lines a and b are parallel lines.
Line t is a transversal.
Corresponding angles are congruent.
Angle 3 is a corresponding angle to the 95-deg angle, so m<3 = 95.
Angles 3 and 4 are supplementary angles since they are a linear pair.
m<3 + m<4 = 180
95 + m<4 = 180
m<4 = 180 - 95
m<4 = 85

3.
Lines a and b are parallel lines.
Line t is a transversal.
Corresponding angles are congruent.
Angle 5 is a corresponding angle to the 49-deg angle, so m<5 = 49.
Angles 5 and 6 are supplementary angles since they are a linear pair.
m<5 + m<6 = 180
49 + m<6 = 180
m<6 = 180 - 49
m<6 = 131



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