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nadezda [96]
3 years ago
6

Find a degree 3 polynomial with real coefficients having zeros 1 and 2-2i and a lead coefficient of 1. Write P in expanded form.

Be sure to write the full equation, including P(x)=.
Mathematics
1 answer:
amm18123 years ago
4 0

Answer:

Step-by-step explanation:

complex roots always occur in pairs.

roots are 1,2-2i,2+2i

P(x)=a(x-a)(x-b)(x-c)

P(x)=1(x-1)[x-(2-2i)][x-(2+2i)]

=1(x-1)[(x-2)+2i][(x-2)-2i]

=(x-1)[(x-2)²-(2i)²]

=(x-1)[(x-2)²-4i²]

=(x-1)[x²-4x+4-4(-1)]

=(x-1)[x²-4x+4+4]

=(x-1)[x²-4x+8]

=x³-4x²+8x-x²+4x-8

=x³-5x²+12x-8

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Find the slope of the line containing the pair of points f(1) = -6 and f(-7) = -6.
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We have that    the slope of the line containing the pair of points f(1) = -6 and f(-7) = -6. is

m=\infty

From the question we are told

Find the slope of the line containing the pair of points f(1) = -6 and f(-7) = -6.

Where Standard form of Equation is

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Generally the equation for the Slope  is mathematically given as

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\huge \huge \huge\huge\mathrm{ \boxed{ \boxed{ \boxed{ \boxed{ \boxed {\boxed{  \huge\mathfrak{ Solution}}}}}}}}

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  • x - 1 =  {x}^{2}  + 49 - 14x

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