Question

A simple random sample of earthquake depths yields the following:

Answer 1

The critical value becomes 2.584 for two tailed test since we have to reject the null hypothesis, t >2.584 or t < -2.584 test stat lie in the rejection region, we have to reject the null hypothesis or claim incorrect.

Data;

• mean = 5.82
• s = 4.93
• n = 600

Test-Static t

Let's calculate the t-value

$t = \frac{x - \mu}{\frac{s}{\sqrt{n} } }$

Substitute the values into the equation and solve;

$t = \frac{x - \mu}{\frac{s}{\sqrt{n} } } \\t = \frac{5.82 - 5}{\frac{4.93}{\sqrt{600} }} \\t = \frac{0.82}{0.201} \\t = 4.079$

The t-value is 4.079.

The allowed significance value = 0.01

The degree of freedom is n -1, which becomes 600 - 1 = 599.

The critical value becomes 2.584 for two tailed test since we have to reject the null hypothesis, t >2.584 or t < -2.584 test stat lie in the rejection region, we have to reject the null hypothesis or claim incorrect.

Learn more on t-test here;

brainly.com/question/6501190