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Sholpan [36]
3 years ago
10

There are 120 students in class 7. It is known that

Mathematics
2 answers:
Radda [10]3 years ago
5 0

Multiply total students by 2/3 to find how many like math:

Like math = 120 x 2/3 = 240/3 = 80 total students like math

Multiply total students by 3/5 to find number of boys:

120 x 3/5 = 360/5 = 72 boys

A) number of girls = total students - boys = 120 -72 = 48 girls

B) from above 80 students like math

C) number of boys that like math = number of students that like math minus girls that like math: 80- 35 = 35 boys like math

pychu [463]3 years ago
3 0
72 boys xjtxkttkftkxktx
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Small boxes contain DVDs, and large boxes contain one gaming machine. Three boxes of gaming machines and a box of DVDs weight 48
miv72 [106K]
DVD weighs 6lbs and game machine weighs 14lbs, so in this case A

in my mind this is what i did...

3(gameMachines) + 5(DVD) = 72lbs
3(gameMachine) + 1 (DVD) = 48lbs

when you subtract, since there is the same number of game machines, they cancel out and your left with
4(DVD) = 24
1 DVD = 6

then just fill in DVD in one of the equations to get the weight of gameMachine
3(gameMachines) + 5(6) = 72lbs
3(gameMachines) = 42
gameMachine = 14
7 0
4 years ago
Read 2 more answers
There are total 360 degrees around a point<br><br> True<br> False
Tom [10]
The answer is true, i hope
4 0
3 years ago
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If using the method of completing the square to solve the quadratic equation x^2+5x-37=0, which number would have to be added to
insens350 [35]

Answer:

1

Step-by-step explanation:

To complete the square, first you must make sure that the coefficient of the x^2 term is 1. Here you have x^2 - 2x - 37 = 0. Since the x^2 term is simply x^2, you do have a coefficient of 1 for the x^2 term.

To find the number you need to add to complete the square, take the coefficient of the x term. Divide it by 2. Then square it.

The x term is -2x. The coefficient of the x term is -2.

Take half of -2 which is -1.

Now square -1 to get 1.

You need to add 1 to complete the square.

brainliest?!?!yes

7 0
3 years ago
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Solve the equation. -5/4n =40
lina2011 [118]
I think the answer is a
8 0
4 years ago
2. A square-based tent has the cross-sectional
ollegr [7]

(a) Length of the height is 2.732 m

(b) Length of the base is 5.466 m

<u>Explanation:</u>

An image is attached for reference.

(a)

In ΔAOB,

sin 30^o = \frac{AO}{AB} \\\\0.5 = \frac{AO}{2} \\\\AO = 1 m

In ΔBGD,

sin 60^o = \frac{BG}{BD} \\\\0.866 = \frac{BG}{2} \\\\BG = 1.732 m

According to the figure, BG = OE = 1.732 m

Height of the tent, AE = AO + OE

                                  = 1 m + 1.732 m

                                  = 2.732 m

(b)

DF = ?

In ΔAOB,

tan 30^o = \frac{AO}{OB} \\\\0.577 = \frac{1}{OB} \\\\OB = 1.733 m\\\\\\

According to the figure, OB = GE = 1.733 m

In ΔBGD,

tan 60^o = \frac{BG}{DG} \\\\1.732 = \frac{1.732}{DG}\\ \\DG = 1m

According to the figure, DE = DG + GE

                                      DE = 1 m + 1.733 m

                                     DE = 2.733 m

Length of the base, DF = 2 X DE

                              DF = 2 X 2.733 m

                               DF = 5.466 m

8 0
3 years ago
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