DVD weighs 6lbs and game machine weighs 14lbs, so in this case A
in my mind this is what i did...
3(gameMachines) + 5(DVD) = 72lbs
3(gameMachine) + 1 (DVD) = 48lbs
when you subtract, since there is the same number of game machines, they cancel out and your left with
4(DVD) = 24
1 DVD = 6
then just fill in DVD in one of the equations to get the weight of gameMachine
3(gameMachines) + 5(6) = 72lbs
3(gameMachines) = 42
gameMachine = 14
The answer is true, i hope
Answer:
1
Step-by-step explanation:
To complete the square, first you must make sure that the coefficient of the x^2 term is 1. Here you have x^2 - 2x - 37 = 0. Since the x^2 term is simply x^2, you do have a coefficient of 1 for the x^2 term.
To find the number you need to add to complete the square, take the coefficient of the x term. Divide it by 2. Then square it.
The x term is -2x. The coefficient of the x term is -2.
Take half of -2 which is -1.
Now square -1 to get 1.
You need to add 1 to complete the square.
brainliest?!?!yes
(a) Length of the height is 2.732 m
(b) Length of the base is 5.466 m
<u>Explanation:</u>
An image is attached for reference.
(a)
In ΔAOB,
In ΔBGD,
According to the figure, BG = OE = 1.732 m
Height of the tent, AE = AO + OE
= 1 m + 1.732 m
= 2.732 m
(b)
DF = ?
In ΔAOB,
According to the figure, OB = GE = 1.733 m
In ΔBGD,
According to the figure, DE = DG + GE
DE = 1 m + 1.733 m
DE = 2.733 m
Length of the base, DF = 2 X DE
DF = 2 X 2.733 m
DF = 5.466 m
