See the picture attached to better understand the problem
we know that
in the right triangle ABC
cos A=AC/AB
cos A=1/3
so
1/3=AC/AB----->AB=3*AC-----> square----> AB²=9*AC²----> equation 1
applying the Pythagoras Theorem
BC²+AC²=AB²-----> 2²+AC²=AB²---> 4+AC²=AB²----> equation 2
substitute equation 1 in equation 2
4+AC²=9*AC²----> 8*AC²=4----> AC²=1/2----> AC=√2/2
so
AB²=9*AC²----> AB²=9*(√2/2)²----> AB=(3√2)/2
the answer isthe hypotenuse is (3√2)/2
Answer:
21
Step-by-step explanation:
because you rupedid lol
The answer is <span>c. 16x2 + 24xy + 9y2.
Since we need trinomial (three term expression) choices a and b are incorrect because they have only two terms.
So, our square trinomial is a</span>² + 2ab + b² or a² - 2ab + b²
a² + 2ab + b² = (a + b)²
a² - 2ab + b² = (a - b)²
Let's check choices c and d:
c) 16x² + 24xy + 9y²
a² = 16x²
a² = (4x)²
a = 4x
b² = 9y²
b² = (3y)²
b = 3y
a² + 2ab + b² = (4x)² + 2 * 4x * 3y + (3y)² = 16x² + 24xy + 9y²
CORRECT
d) 49x² - 70xy + 10y²
a² = 49x²
a² = (7x)²
a = 7x
b² = 10y²
b² = (y√10)²
b = y√10
a² + 2ab + b² = (7x)² + 2 * 7x * y√10 + (y√10)² = 49x² + 14xy√10 + 10y²
INCORRECT
So, c) is correct answer
The answer is A because say there is point H between F and G the point would be considered summarised by F and G