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34kurt
2 years ago
5

If a circle has a diameter of 11.5 feet, what is the area?

Mathematics
1 answer:
OverLord2011 [107]2 years ago
3 0

Answer:

103.87 ft.

In this case, area equals \pi r^2

The diameter is 2r

But before worrying about anything else, we must start the problem. Let's do that now.

The first step is to find the broken-down form of the area.

A = \frac{1}{4} \pi d^2

Next, break this equation into a solvable definition.

\frac{1}{4} * \pi  * 11.5

Lastly, solve this equation, and round.

A ≈ 103.86891~ft^2

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Find the value of g(-1)
Anna11 [10]

Answer:

g(-1) = -3

Step-by-step explanation:

g(-1) is the y value of the graph when x = -1

when x=-1 y=-3

g(-1) = -3

6 0
3 years ago
In 2010, the world's largest pumpkin weighed 1,810 kilograms. An average-sized pumpkin weighs 5,000 grams.
jekas [21]

Answer:

1,805 kg.

Step-by-step explanation:

We have been given that in 2010, the world's largest pumpkin weighed 1,810 kilograms. An average-sized pumpkin weighs 5,000 grams. We are asked to find the how much the world's largest pumpkin weighs than an average pumpkin.

First of all, we will convert the weight of average pumpkin in kilograms by dividing 5,000 by 1000 as 1 kg equals 1,000 gm.

\text{The weight of average pumpkin}=\frac{5000\text{ gm}}{\frac{\text{1000 gm}}{\text{ 1 kg}}}

\text{The weight of average pumpkin}=5000\text{ gm}\times \frac{\text{ 1 kg}}{\text{1000 gm}}

\text{The weight of average pumpkin}=5\text{ kg}

Now, we will subtract the weight of average pumpkin from world's largest pumpkin's weight.

1,810\text{ kilograms}-5\text{ kilograms}=1,805\text{ kilograms}

Therefore, the 2010 world-record pumpkin weighs 1,805 kilograms more than an average-sized pumpkin.

3 0
3 years ago
Read 2 more answers
A-attached earlobes a-unattached earlobes if a is the allele for having attached earlobes, what percentage of offspring will hav
Scorpion4ik [409]

The percentage of the offspring that will have atatched earlobes as the dominant trait, is: 50%.

What is a Dominant Trait?

A dominant trait surpresses a recessive trait, and expresses itself. The allele of a dominant trait is usally denoted using capital letters.

Given the following traits:

A - attached earlobes (dominant allele)

a - unattached earlobes (recessive allele)

A cross between Aa and aa is shown in the image attached below.

The offspring having attached earlobes = 2 Aa = 50%.

50% of the osspring will have attached earlobes.

Learn more about dominant trait on:

brainly.com/question/16616523

4 0
2 years ago
ASAP some answer this ASAP
tatyana61 [14]
This answe would have to be (-3,7)
5 0
1 year ago
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4(2x - 5) + 15 = 11 Write the steps you will use to solve the equation and explain each step.
vagabundo [1.1K]
First, multiply 4*2x-4*-5= 8x-20.
Second, add 15 to 8x-20
Third, that would equal 8x-20+15=11 
Fourth, 15+-20= -5 
Fifth, 8x-5=11
Sixth, add +5 to -5 and +5 to 11= 8x=16 
Last, do 8x/8x and 16/8x 
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6 0
3 years ago
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