Answer:
g(-1) = -3
Step-by-step explanation:
g(-1) is the y value of the graph when x = -1
when x=-1 y=-3
g(-1) = -3
Answer:
1,805 kg.
Step-by-step explanation:
We have been given that in 2010, the world's largest pumpkin weighed 1,810 kilograms. An average-sized pumpkin weighs 5,000 grams. We are asked to find the how much the world's largest pumpkin weighs than an average pumpkin.
First of all, we will convert the weight of average pumpkin in kilograms by dividing 5,000 by 1000 as 1 kg equals 1,000 gm.



Now, we will subtract the weight of average pumpkin from world's largest pumpkin's weight.

Therefore, the 2010 world-record pumpkin weighs 1,805 kilograms more than an average-sized pumpkin.
The percentage of the offspring that will have atatched earlobes as the dominant trait, is: 50%.
What is a Dominant Trait?
A dominant trait surpresses a recessive trait, and expresses itself. The allele of a dominant trait is usally denoted using capital letters.
Given the following traits:
A - attached earlobes (dominant allele)
a - unattached earlobes (recessive allele)
A cross between Aa and aa is shown in the image attached below.
The offspring having attached earlobes = 2 Aa = 50%.
50% of the osspring will have attached earlobes.
Learn more about dominant trait on:
brainly.com/question/16616523
This answe would have to be (-3,7)
First, multiply 4*2x-4*-5= 8x-20.
Second, add 15 to 8x-20
Third, that would equal 8x-20+15=11
Fourth, 15+-20= -5
Fifth, 8x-5=11
Sixth, add +5 to -5 and +5 to 11= 8x=16
Last, do 8x/8x and 16/8x
The answer is x=2