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Burka [1]
3 years ago
15

Find the missing term. 7-147 × 798 = 718 × 7-38 ×

Mathematics
1 answer:
krek1111 [17]3 years ago
8 0

Answer:look at the picture

Step-by-step explanation:

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What is the value of this expression? (−2)^5
dalvyx [7]

Answer:

-32

Step-by-step explanation:

=(-2)^5

=-2*-2*-2*-2*-2-2

-2*-2=4

-2*-2=4

-2

4*4=16

16*-2=-32

Hope this helps :) ❤❤❤

6 0
3 years ago
Together, Bobs shoes weigh about 1 kilograms. Each shoe weighsabout how many grams.
kolbaska11 [484]
Divide 1 kilogram by how much shoes are there.
8 0
3 years ago
Read 2 more answers
EP6. Abby works at a job that starts out paying $15 per hour. Each year she continues
Artemon [7]

Answer:

$64.83.

Step-by-step explanation:

Each year the multiplier fffor her new rate will be 1.05.

So after 30 years her hourly rate will be  15 * 1.05^30

= $64.83

6 0
2 years ago
Willis tower in Chicago is 1450 feet tall. The John Hancock Center in Chicago is 1127 feet tall. Suppose you are asked to build
gayaneshka [121]

Answer:

Small Scale replica of John Hancock tower is approximately 2.33 m.

Step-by-step explanation:

Given:

Height of Willis tower = 1450 ft

Height of John Hancock Center = 1127 ft

Small Scale replica of Willis tower = 3 m

We need to find Small Scale replica of John Hancock tower.

First we will find the per meter scale of Willis tower and then using the same we will use to find the Small Scale replica height of John Hancock tower.

For 3 meter scaling = 1450 ft

So for 1 meter scaling = Number of foots in 1 meter Scaling

By Using Unitary method we get;

Number of foots in 1 meter Scaling = \frac{1450}{3} = 483.333 \ ft

Now we had 1 meter scaling as 483.333 ft and we need to find meter scaling for 1127.

So again Using Unitary method we get;

Small Scale replica of John Hancock = \frac{1127}{483.333} = 2.331 \ m

Rounding to nearest hundred we get;

Small Scale replica of John Hancock tower is approximately 2.33 m.

8 0
3 years ago
How to solve number 4
s2008m [1.1K]
Find the first semicircle area
Area semicircle can be determined by dividing the full area of circle by 2.
The first semicircle radius is 5 cm
semicircle area = 1/2 circle area
semicircle area = 1/2 × π × r²
semicircle area = 1/2 × 3.14 × 5²
semicircle area = 1/2 × 3.14 × 25
semicircle area = 39.25 cm²

Find the second semicircle area
Because the dimension of the second semicircle is congruent to the first semicircle, they have similar area measurement, 39.25 cm².

Find the quarter circle area
The area of quarter circle can be determined by dividing the full area of a circle by 4.
q circle = 1/4 × area of circle
q circle = 1/4 × π × r²
q circle = 1/4 × 3.14 × 10²
q circle = 1/4 × 314
q circle = 78.5 cm²

To find the entire area, add the area above together
area = first semicircle + second semicircle + q circle
area = 39.25 + 39.25 + 78.5
area = 157

The area of shaded region is 157 cm²
4 0
3 years ago
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