Either graph the points, or you can divide x by y for each set of points and if your answers are the same, then it is linear.
Hope it helps!
You know that the slope, m=5. You have a point (6,7) as (x,y). The slope-intercept form is y=mx+b. Plug in the number for x,y, and m, and then you would be able to find b using the slope-intercept form. Then rewrite the equation as y=5x+b, which you just found b.
(Here's the first step. 7=5(-6)+b). Find b, and then write the slope-intercept form as y=5x+b.
Answer:
a reflection over the x-axis
Step-by-step explanation:
say you plotted (1,1) and the plotted (-1,1). The result would be a reflection over the x-axis.
To solve this, you have to know that the first derivative of a function is its slope. When an interval is increasing, it has a positive slope. Thus, we are trying to solve for when the first derivative of a function is positive/negative.
f(x)=2x^3+6x^2-18x+2
f'(x)=6x^2+12x-18
f'(x)=6(x^2+2x-3)
f'(x)=6(x+3)(x-1)
So the zeroes of f'(x) are at x=1, x=-3
Because there is no multiplicity, when the function passes a zero, he y value is changing signs.
Since f'(0)=-18, intervals -3<x<1 is decreasing(because -3<0<1)
Thus, every other portion of the graph is increasing.
Therefore, you get:
Increasing: (negative infinite, -3), (1, infinite)
Decreasing:(-3,1)
