Answer:
3
Step-by-step explanation:
You want a number that if it is multiplied by 3 1/3 the result will be 10. Let the number be x
3 1/3 * x = 10 Change to a mixed number
10/3 * x = 10 Multiply by 3/10
(10/3)*x * 3/10 = 10 * 3/10 Combine
x = 10*3 / 10 Simplify
x = 30/10 = 3
Answer:
x≤ -21/4
Step-by-step explanation:
The pattern in the first set of numbers is times 3, to find the next number multiply 54 by 3 to get 162.
The pattern in the second set of numbers is plus 4, to find the next number add 4 to 0 to get 4.
The pattern in the last set of numbers timed -3, to find the next number multiply -81 by -3 to get 243.
![\left[\begin{array}{ccc}1&3&7\\1&1&1\end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%263%267%5C%5C1%261%261%5Cend%7Barray%7D%5Cright%5D%20)
multiply 2nd row by -1 and add to first row
![\left[\begin{array}{ccc}0&2&6\\1&1&1\end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%262%266%5C%5C1%261%261%5Cend%7Barray%7D%5Cright%5D%20)
divide the 1st row by 2
![\left[\begin{array}{ccc}0&1&3\\1&1&1\end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%261%263%5C%5C1%261%261%5Cend%7Barray%7D%5Cright%5D%20)
multiply the first row by -1 and add to 2nd row
![\left[\begin{array}{ccc}0&1&3\\1&0&-2\end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%261%263%5C%5C1%260%26-2%5Cend%7Barray%7D%5Cright%5D%20)
now we know
y+3=0
x-2=0
therefor
y=-3
x=2
