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Gnoma [55]
3 years ago
12

Can someone help me answer this please!!!

Mathematics
1 answer:
galben [10]3 years ago
3 0
Hello!

Your answer is...

14x/x-2 - 28/x-2 = ==> 14


- Dukuccino<span>©</span> ❤


Hope this helps! ^^ Brainlyist please
You might be interested in
What is the 4th term in the sequence b(n)=1(-2)^n-1
marishachu [46]

Answer:

<h2>The answer is 8</h2>

Step-by-step explanation:

From the question the formula for the sequence is

b(n) = 1 ({ - 2})^{n - 1}

where

n is the nth term in the sequence

Since we are finding the 4th term n = 4

Substitute this value of n into the above formula

That's

b(4) = 1 ({ - 2})^{4 - 1} \\  = 1 ({ - 2})^{3}  \\  =   { - 2}^{3}

We have the final answer as

<h3>8</h3>

Hope this helps you

7 0
3 years ago
&gt; Question A normal distribution is observed from the number of points per game for a certain basketball player. If the mean
densk [106]

Answer:

The probability that in a randomly selected game, the player scored greater than 24 points is 0.0013 or 0.13%

Step-by-step explanation:

Given that

Mean = μ = 15 points

SD = σ = 3 points

For calculating probability for a data point, first of all we have to calculate the z-score of the value.

We have to find the probability of score greater than 24, then the z-score of 24 is:

z-score = (x-μ)/σ

z = (24-15)/3

z = 9/3

z = 3

Now we have to use the z-score table to find the probability of z<3 then it will be subtracted from 1 to find the probability of z>3

So,

P(z3) = 1 - P(z

Converting into percentage

0.0013 * 100 = 0.13%

Hence,

The probability that in a randomly selected game, the player scored greater than 24 points is 0.0013 or 0.13%

8 0
2 years ago
Crash testing is a highly expensive procedure to evaluate the ability of an automobile to withstand a serious accident. A simple
Veseljchak [2.6K]

Answer:

The 95% confidence interval is (-0.2451, 06912)

Step-by-step explanation:

From the question, we have;

The number of small cars in the sample of small cars, n₁ = 12

The number of small cars that were totaled, x = 8

The number of large cars in the sample of small cars, n₂ = 15

The number of large cars that were totaled, y = 5

Therefore, the proportion of small cars that were totaled, pX = x/n₁

∴ pX = 8/12 = 2/3

The proportion of large cars that were totaled, pY = y/n₁

∴ pY = 5/15 = 1/3

The 95% confidence interval for the difference pX - pY is given as follows;

pX-pY\pm z^{*}\sqrt{\dfrac{pX\left (1-pX  \right )}{n_{1}}+\dfrac{pY\left (1-pY  \right )}{n_{2}}}

\dfrac{2}{3} -\dfrac{1}{3} \pm 1.96 \times \sqrt{\dfrac{\dfrac{2}{3} \times \left (1-\dfrac{2}{3}   \right )}{12}+\dfrac{\dfrac{1}{3} \times \left (1-\dfrac{1}{3}   \right )}{15}}

Therefore, we have;

\therefore 95\% \  CI = \dfrac{1}{3} \pm 0.3578454

The 95% confidence interval, CI = (-0.2451, 06912)

6 0
2 years ago
6 times the sum of 3 consecutive odd intergers is -18
Lyrx [107]
The answer: The 3 (three) consecutive odd integers are: -3, -1, 1.
_____________________________________________
Explanation:
_______________
To represent 3 (three consecutive odd integers):
____________________________________
Let "x" be the first odd integer.
____________________________________
Let "(x+2)" be next consecutive odd integer.
____________________________________
Let "(x+4") be the third odd integer.
____________________________________
The sum of these three consecutive odd integers:
__________________________________________
x + (x + 2) + (x + 4) = x + x + 2 + x + 4 = 3x + 6 ;
_________________________________________
Six ("6") times the sum of these 3 (three) consecutive odd integers =
_________________
6*(3x+6) = 6(3x + 6) = -18 (as given in the problem).
_____________________________________________
Given: 6(3x + 6) = -18 ; We can divide EACH SIDE of the equation by "6", to cancel the "6" on the left-hand side into a "1"; 
__________________________________________
{6(3x + 6) } / 6 = -18 / 6 ;  to get:
________________________________________
3x + 6 = -3 ; Now, we can subtract "6" from EACH SIDE of the equation:
__________________________________
3x + 6 - 6 = -3 - 6 ; to get:
__________________________________
3x = -9 ; Now, we can divide EACH SIDE of the equation by "3"; to isolate "x" on one side of the question; and solve for "x" ;
___________________________________
3x / 3 = -9 / 3 ;  x = - 3 ;
_____________________
Remember, from above:
__________________________
Let "x" be the first odd integer.  We know that "x = -3".
         Is this an odd integer? Yes!
____________________________________
Let "(x+2)" be next consecutive odd integer.  So (x+2) = (-3+2) = -1.
        Is this an odd integer? Yes!  Is this "{-1}" the next consecutive odd integer with respect to "{-3}"? Yes!
____________________________________
Let "(x+4") be the third odd integer. So (x+4) = (-3+4) = 1.
       Is this an odd integer? Yes!  Is this "{1"} the next consecutive odd integer with respect to "{-1}"? Yes!
___________________________
So, our 3 (three) consecutive odd integers are: -3, -1, 1.
___________________________
To check our work: Is 6 times the sum of our 3 consecutive odd integers, equal to "(-18)" ?

The sum of our 3 consecutive odd integers = -3 + (-1) + 1 = -3 - 1 + 1 = -3.

6 * -3 = ? -18? Yes!
___________________________





3 0
3 years ago
What is the recursive rule for the following sequence: -5, -3, -1, 1…
Irina18 [472]
a_{n} = a_{n-1} + 2

So C.
4 0
3 years ago
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