The answer is 19m^2 , 333m^2 , 129m^2 , 32m^2
THE LEAST COMMON MULTIPLE WILL BE HIGHER THAN THE greatest common factor as long as the 2 numbers are different.
The stiffness of one short spring is 13500 N/m
<em><u>Solution:</u></em>
We are given a chain with number of spring N = 30 and linked end to end ( in series) and stiffness of this chain is 450 N/m
We have to find the stiffness of one short spring
The springs are identical, which means they have same stiffness
<em><u>The stiffness of one spring in series is given as:</u></em>
Where,
N is the number of springs
is the stiffness of one spring
is the stiffness of this chain
Substituting,
Therefore,
Thus the stiffness of one short spring is 13500 N/m
Answer: The answer would be 5^3
Step-by-step explanation:
5 x 5 x 5= 125
Answer:
2/3
Step-by-step explanation:
4/9×3/2=2/3 The answers provided are all wrong