Answer:
8 1/2 miles
Step-by-step explanation:
Please use " ' " to indicate fractions:
Andrea rode her bike 3 2/3 miles on saturday and 4 5/6 miles on sunday.
Add together 3 2/3 and 4 5/6. The LCD is 6, so 3 2/3 should be rewritten as 3 4/6. Now 3 4/6 and 4 5/6 have the same denominator, 6.
3 4/6
+4 5/6
-----------
7 9/6. Note that 9/6 = 1 1/2, so rewrite
7 9/6 as 8 3/6, or 8 1/2.
She biked 8 1/2 miles in all.
Additive inverses combine to get 0. So, k is -1.4. The sum is 0. Hopefully that will help.
We know that
[area of a regular hexagon]=6*[area of one <span>equilateral triangle]
</span>210.44=6*[area of one equilateral triangle]
[area of one equilateral triangle]=210.44/6-----> 35.07 cm²
[area of one equilateral triangle]=b*h/2
h=7.794 cm
b=2*area/h------> b=2*35.07/7.794------>b= 9 cm
the length side of a regular hexagon is 9 cm
<span>applying the Pythagorean theorem
</span>r²=h²+(b/2)²------>r²=7.794²+(4.5)²------> r²=81--------> r=9 cm
<span>this last step was not necessary because the radius is equal to the hexagon side------> (remember the equilateral triangles)
</span>
the answer is
the radius is 9 cm
Answer:
I believe that it would be 10^3. (10x10x10)
Sorry if I'm wrong I'm just a little confused with the question you asked :/
Hi there!
I can see why you've posted a question like this here - For adding, subtracting, multiplying, or dividing fractions by whole numbers can be difficult to come out with a precise answer, so let me make it look easier for you!
So, the steps are:
Smush the 2 (whole number) and the 2 (the numerator of the fraction) together on top so its (2)(2) over 6. I can show you what I mean, if you'd like.
This is what it should look like.
Now, what is 2 times 2? You can use a calculator for this part.
Now, we can get to the last part, my favorite one!
Simplify 
down to 
.
How did we do it? EASY!
See what number does evenly into both numerators and denominators. In this case, 2 goes into 4 twice, and 2 goes into 6 three times, so we're left with our beautiful answer .
That wasn't so bad, was it? You can use this as a guide for figuring out math problems like these, in case you're stuck again. But just in case, message me if you need anymore help! :D
