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2 years ago

Subtract. 13 5/8- 3 2/3 HELPPPP IM LITERALLY GONNA FAIL

2 answers:

7 0

First let’s just subtract the whole numbers. 13 5/8 -3= 10 5/8

next let’s find the LCM, or least common multiple of the denominators for the fractions. 10 5/8 = 10 15/24
2/3= 16/24

now last, subtract these new fractions.
10 15/24 - 16/24 = 9 23/24

Svetradugi [14.3K]2 years ago

6 0

13/1 × 5/8 - 3/1 × 2/3

= 13×5 / 1×8 - 3×2 / 1×3

= 65/8 - 6/3

= 195/24 - 48/24

=147/24

=49/8

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$\bold{\huge{\underline{ Solution }}}$

<h3>Given :- </h3>

• $\sf{ Polynomial :- ax^{2} + bx + c }$

• The zeroes of the given polynomial are α and β .

<h3>Let's Begin :- </h3>

Here, we have polynomial

$\sf{ = ax^{2} + bx + c }$

We know that, 

Sum of the zeroes of the quadratic polynomial

$\sf{ {\alpha} + {\beta} = {\dfrac{-b}{a}}}$

And 

Product of zeroes

$\sf{ {\alpha}{\beta} = {\dfrac{c}{a}}}$

Now, we have to find the polynomials having zeroes :-

$\sf{ {\dfrac{{\alpha} + 1 }{{\beta}}} ,{\dfrac{{\beta} + 1 }{{\alpha}}}}$

Therefore ,

Sum of the zeroes

$\sf{ ( {\alpha} + {\dfrac{1 }{{\beta}}} )+( {\beta}+{\dfrac{1 }{{\alpha}}})}$

$\sf{ ( {\alpha} + {\beta}) + ( {\dfrac{1}{{\beta}}} +{\dfrac{1 }{{\alpha}}})}$

$\sf{( {\dfrac{ -b}{a}} ) + {\dfrac{{\alpha}+{\beta}}{{\alpha}{\beta}}}}$

$\sf{( {\dfrac{ -b}{a}} ) + {\dfrac{-b/a}{c/a}}}$

$\sf{ {\dfrac{ -b}{a}} + {\dfrac{-b}{c}}}$

$\bold{{\dfrac{ -bc - ab}{ac}}}$

Thus, The sum of the zeroes of the quadratic polynomial are -bc - ab/ac

Product of zeroes

$\sf{ ( {\alpha} + {\dfrac{1 }{{\beta}}} ){\times}( {\beta}+{\dfrac{1 }{{\alpha}}})}$

$\sf{ {\alpha}{\beta} + 1 + 1 + {\dfrac{1}{{\alpha}{\beta}}}}$

$\sf{ {\alpha}{\beta} + 2 + {\dfrac{1}{{\alpha}{\beta}}}}$

$\bold{ {\dfrac{c}{a}} + 2 + {\dfrac{ a}{c}}}$

Hence, The product of the zeroes are c/a + a/c + 2 .

We know that, 

For any quadratic equation

$\sf{ x^{2} + ( sum\: of \:zeroes )x + product\:of\: zeroes }$

$\bold{ x^{2} + ( {\dfrac{ -bc - ab}{ac}} )x + {\dfrac{c}{a}} + 2 + {\dfrac{ a}{c}}}$

Hence, The polynomial is x² + (-bc-ab/c)x + c/a + a/c + 2 .

<h3>Some basic information :-</h3>

• Polynomial is algebraic expression which contains coffiecients are variables.

• There are different types of polynomial like linear polynomial , quadratic polynomial , cubic polynomial etc.

• Quadratic polynomials are those polynomials which having highest power of degree as 2 .

• The general form of quadratic equation is ax² + bx + c.

• The quadratic equation can be solved by factorization method, quadratic formula or completing square method.

6 0

2 years ago

Answer n.8 for me pls

Nimfa-mama [501]

Answer:

Step-by-step explanation:

(13)2−(2x+7)=0

19x2−2x−7=0

9(19x2−2x−7)=9(0)

x2−18x−63=0

(x−21)(x+3)=0

Therefore, the value of x are

x - 21 = 0 and x + 3 = 0

x = 21 x = -3

5 0

4 years ago

Find the slope and y-intercept of the line through the given points. (1-8)

Arlecino [84]

Answer:

You need a graph chart for this, people won't really be able to help that much, the most they can give you is the y intercept for these points.

Step-by-step explanation:

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3 years ago