Answer: 0.75
Step-by-step explanation:
Given : Interval for uniform distribution : [0 minute, 5 minutes]
The probability density function will be :-
The probability that a given class period runs between 50.75 and 51.25 minutes is given by :-
![P(x>1.25)=\int^{5}_{1.25}f(x)\ dx\\\\=(0.2)[x]^{5}_{1.25}\\\\=(0.2)(5-1.25)=0.75](https://tex.z-dn.net/?f=P%28x%3E1.25%29%3D%5Cint%5E%7B5%7D_%7B1.25%7Df%28x%29%5C%20dx%5C%5C%5C%5C%3D%280.2%29%5Bx%5D%5E%7B5%7D_%7B1.25%7D%5C%5C%5C%5C%3D%280.2%29%285-1.25%29%3D0.75)
Hence, the probability that a randomly selected passenger has a waiting time greater than 1.25 minutes = 0.75
Answer: 11.05
Step-by-step explanation:
Divide 5.20 by 8 to find the price of each bag (which is .65 cents.) Multiple .65 by 20 (13). 15% of 13 is 1.95. 13 - 1.95 is 11.05
PS: 1.95 is the discount. Hope this helps. Have a good day.
Answer:
-18/3
Step-by-step explanation:
Answer:
3.471 + 7.2516 x
Step-by-step explanation:
Given the data:
(1,3) (2,0) (5,-8) (9, -25) .
X:
1
2
5
9
Y:
3
0
-8
-25
The line of best fit for the data given can be obtained using an online regression calculator :
The equation of best fit for the data is thus;
Best fit equation; y = -3.471 + 7.2516x
Intercept = - 3.471 ;
Slope = 7.2516
-3 from all ends to get 1<-3x<3 then divide by -3 on all ends to get -1/3>x>-1 you flip the sign because of the negative,
