Answer:
The probability is 0.8
Step-by-step explanation:
The key to answering this question is considering the fact that the two married employees be treated as a single unit.
Now what this means is that we would be having 8 desks to assign.
Mathematically, the number of ways to assign 8 desks to 8 employees is equal to 8!
Now, the number of ways the couple can interchange their desks is just 2 ways
Thus, the number of ways to assign desks such that the couple has adjacent desks is 2(8!)
The number of ways to assign desks among all six employees randomly is 9!
Thus, the probability that the couple will have adjacent desks would be ;
2(8!)/9! = 2/9
This means that the probability that the couple have non adjacent desks is 1-2/9 = 7/9 = 0.77778
Which is 0.8 to the nearest tenth of a percent
C: 12/35a^3
2 multiplied by 6 is 12.
5 multiplied by 7 is 35.
a^1+a^2=a^3.
Answer:
Step-by-step explanation:
12x −3y=36 ⇔ 3y = 12x - 36
y = 4x - 12
y = 0 ⇔ 4x - 12 = 0 ⇔ 4x = 12 ⇔ x = 12/4 = 3
So (0 ; - 12) and (3 ; 0)
Answer:
1,436.8
Step-by-step explanation:
Answer:
(0,3) is the solution set for given system.
Step-by-step explanation:
Given that:
3x+4y=12 ------- eq1
2x-3y= -9 ------- eq2
Multiplying eq1 with 2 and eq2 with 3 we get:
6x + 8y = 24 --------- eq1
6x - 9y = -27 -------- eq2
Subtracting eq2 from 1 we get:
17y = 51
Dividing both sides by 17 we get:
y = 3
Putting value of 3 in eq1 we get:
3x + 4(3) = 12
3x + 12 = 12
3x = 0
Dividing both sides by 3
x = 0
So the solution set will be: (0,3)
i hope it will help you.