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strojnjashka [21]
2 years ago
8

X=6 is a solution to the inequality x−5≤ 10 True or False?

Mathematics
2 answers:
vekshin12 years ago
6 0

Answer:

  • \boxed{\sf{FALSE}}
  • \boxed{\sf{x\leq 15}}

Step-by-step explanation:

Isolate the term of x from one side of the equation.

<h3>x-5≤10</h3>

<u>First, add by 5 from both sides.</u>

\sf{x-5+5\leq10+5}

<u>Solve.</u>

<u>Add the numbers from left to right.</u>

\sf{10+5=15}

\Longrightarrow: \boxed{\sf{x\leq 15}}

  • <u>Therefore, the solution is x≤15, which is our answer.</u>

I hope this helps you! Let me know if my answer is wrong or not.

Korolek [52]2 years ago
5 0
<h3>hello!</h3>

Let's solve this inequality.

First, we should add 5 to both sides:-

x≤10+5

x≤15

Remember, the "≤" sign means "less than or equal to"

So is x=6 a solution to the inequality x≤15? Will this solution make the inequality true?

Yes.

<h3>note:-</h3>

Hope everything is clear; if you need any explanation/clarification, kindly let me know, and I will comment and/or edit my answer :)

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2 years ago
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The sample drawn is of size, <em>n</em> = 5046.

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CI_{p}=[\hat p-z_{(\alpha /2)}\times\sqrt{\frac{\hat p (1-\hat p)}{n} },\ \hat p+z_{(\alpha /2)}\times\sqrt{\frac{\hat p (1-\hat p)}{n} }]

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CI_{p}=[\hat p-z_{(\alpha /2)}\times\sqrt{\frac{\hat p (1-\hat p)}{n} },\ \hat p+z_{(\alpha /2)}\times\sqrt{\frac{\hat p (1-\hat p)}{n} }]\\=[0.31-2.33\times \sqrt{\frac{0.31\times(1-0.33)}{5046} },\ 0.31+2.33\times \sqrt{\frac{0.31\times(1-0.33)}{5046} } ]\\=[0.31-0.0152,\ 0.31+0.0152]\\=[0.2948,0.3252]\\\approx[0.30,\ 0.33]

Thus, the 98% confidence interval [0.30, 0.33] implies that there is a 0.98 probability that the population proportion of people who refuse evacuation is between 0.30 and 0.33.  

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