Hello there.
Question: <span>Which of these is equal to cos 19°?
Answer: There aren't any options so i can only give the value for it which is 0.9455
</span>Hope This Helps You!
Good Luck Studying ^-^
Answer: The correct answer is B.
Step-by-step explanation: To simplify a square root, you take the factors of the value in the square root and see the greatest factor that is a square. In this case, 49 is the greatest square factor of 98. You take the square root of 49, which is 7. 7 goes outside the radicand. Leave 2 inside the radical because 49 x 2 = 98. Hence, the correct answer is B.
Answer:
Distance from the airport = 894.43 km
Step-by-step explanation:
Displacement and Velocity
The velocity of an object assumed as constant in time can be computed as

Where
is the displacement. Both the velocity and displacement are vectors. The displacement can be computed from the above relation as

The plane goes at 400 Km/h on a course of 120° for 2 hours. We can compute the components of the velocity as


The displacement of the plane in 2 hours is


Now the plane keeps the same speed but now its course is 210° for 1 hour. The components of the velocity are


The displacement in 1 hour is


The total displacement is the vector sum of both



The distance from the airport is the module of the displacement:


tan 52 = 180/a; a = 180/tan 52
tan 43 = 180/b; b = 180/tan 43
you need to calculate, a-b = 180/tan 52 - 180/tan 43
substitute the value of tan thetas, and calculate it simply...
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