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Rzqust [24]
3 years ago
6

Triangle ABC is to be dilated through point P with a scale factor of 3. How many units away from point A along ray PA will A’ be

located?

Mathematics
2 answers:
mylen [45]3 years ago
6 0

Answer:

10 units

Step-by-step explanation:

Person above me is right

drek231 [11]3 years ago
3 0

Answer:

A' will be located 10 units from point A along ray PA

Step-by-step explanation:

we know that

The scale factor is equal to 3

To obtain PA', multiply PA by the scale factor

so

PA'=PA*3

PA=5 units

substitute

PA'=(5)*3=15 units

AA'=PA'-PA=15-5=10 units

therefore

A' will be located 10 units from point A along ray PA

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What is the missing numerator? (4 points)
kozerog [31]

Answer:

\frac{x}{7} - \frac{3}{8} = \frac{27\\}{56}

Step-by-step explanation:

C

6 x 8 = 32

7 x 3 = 21

32 - 21 = 27

7 0
3 years ago
Maria works as a part- time waitress and earns $30 per day plus 2% of all sales of food and drinks during the day
ollegr [7]

Answer:

y = 30 + 0.02x

Step-by-step explanation:

Required

Write an equation to present her daily earnings?

Let daily sales be represented by x and daily earnings be represented by y.

y is calculated as thus;

y = Earnings + Commission * Sales

y = 30 + 2\% * x

Convert percentage to decimal

y = 30 + 0.02 * x

y = 30 + 0.02x

Hence, her daily earnings is y = 30 + 0.02x

5 0
3 years ago
Please help :)))) ( attachment )
Anastaziya [24]
Let,
f(x) = -2x+34
g(x) = (-x/3) - 10
h(x) = -|3x|
k(x) = (x-2)^2

This is a trial and error type of problem (aka "guess and check"). There are 24 combinations to try out for each problem, so it might take a while. It turns out that 

g(h(k(f(15)))) = -6
f(k(g(h(8)))) = 2

So the order for part A should be: f, k, h, g
The order for part B should be: h, g, k f
note how I'm working from the right and moving left (working inside and moving out).


Here's proof of both claims

-----------------------------------------

Proof of Claim 1:

f(x) = -2x+34
f(15) = -2(15)+34
f(15) = 4
-----------------
k(x) = (x-2)^2
k(f(15)) = (f(15)-2)^2
k(f(15)) = (4-2)^2
k(f(15)) = 4
-----------------
h(x) = -|3x|
h(k(f(15))) = -|3*k(f(15))|
h(k(f(15))) = -|3*4|
h(k(f(15))) = -12
-----------------
g(x) = (-x/3) - 10
g(h(k(f(15))) ) = (-h(k(f(15))) /3) - 10
g(h(k(f(15))) ) = (-(-12) /3) - 10
g(h(k(f(15))) ) = -6

-----------------------------------------

Proof of Claim 2:

h(x) = -|3x|
h(8) = -|3*8|
h(8) = -24
---------------
g(x) = (-x/3) - 10
g(h(8)) = (-h(8)/3) - 10
g(h(8)) = (-(-24)/3) - 10
g(h(8)) = -2
---------------
k(x) = (x-2)^2
k(g(h(8))) = (g(h(8))-2)^2
k(g(h(8))) = (-2-2)^2
k(g(h(8))) = 16
---------------
f(x) = -2x+34
f(k(g(h(8))) ) = -2*(k(g(h(8))) )+34
f(k(g(h(8))) ) = -2*(16)+34
f(k(g(h(8))) ) = 2
5 0
4 years ago
Ify -36.<br> What is the square root for -36 ?
AysviL [449]
Answer:
6 i
Explanation:
7 0
3 years ago
If two dice are rolled one time find the probability <br> A 3 on one die or both dice
Anastaziya [24]

|\Omega|=6^2=36\\|A|=1\cdot5\cdot2+1=11\\\\P(A)=\dfrac{11}{36}\approx30.6\%

3 0
3 years ago
Read 2 more answers
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