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1 year ago

11

Kurtis is watching a movie. The movie lasts 280 min. Kurtis has watched 30% of the movie so far. How many minutes of the movie h

as Kurtis watched? Show your Work.

1 answer:

Komok [63]1 year ago

8 0

Answer:

ok so this is just multiplycation

30% is also 0.3 so

280*0.3=84

84 minutes or

1 hour 24 minutes

Hope This Helps!!!

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Use a positive or negative number to represent a stock market loss of $1,500.

Natasha_Volkova [10]

Answer:

negative

Step-by-step explanation:

negative because you are losing something

7 0

2 years ago

Solve<br> for x:<br> 3(1 - 3x) = 2(-4x + 7)

djverab [1.8K]

Answer:

x= -11

Step-by-step explanation:

distribute the 3 and the 2: 3 - 9x = -8x + 14

add 9x from both sides and subtract 14 from both sides: -11 = x

x = -11

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2 years ago

6(3X +5 ) = 7(2x +2)

boyakko [2]

Answer:

X=-4 last answer i got i hope it is helpful have a nice day

Step-by-step explanation:

Let's solve your equation step-by-step.

6(3x+5)=7(2x+2)

Step 1: Simplify both sides of the equation.

6(3x+5)=7(2x+2)

(6)(3x)+(6)(5)=(7)(2x)+(7)(2)(Distribute)

18x+30=14x+14

Step 2: Subtract 14x from both sides.

18x+30−14x=14x+14−14x

4x+30=14

Step 3: Subtract 30 from both sides.

4x+30−30=14−30

4x=−16

Step 4: Divide both sides by 4.

4x

4

=

−16

4

x=−4

Answer:

x=−4

5 0

2 years ago

Read 2 more answers

F(x) = 3x<br> g(x) = x2 – 5x - 9<br> Find (fºg)(x).

Eddi Din [679]

Answer:

$\boxed{(f.g)(x) = 3 {x}^{3} - 15 {x}^{2} - 27x}$

Given:

$f(x) = x + 2 \\ \\ g(x) = 3x + 5$

To Find:

$(f.g)(x) = f(x) \times g(x)$

Step-by-step explanation:

$= > f(x) \times g(x) = (3x)( {x}^{2} - 5x - 9) \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = (3x \times {x}^{2} ) - (3x \times 5x) - (3x \times 9)\\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 3 {x}^{3} - 15 {x}^{2} - 27x$

8 0

3 years ago

Find the first three terms in the expansion , in ascending power of x , of (2+x)^6 and obtain the coefficient of x^2 in the expa

Nataly_w [17]

Answer:

The first 3 terms in the expansion of $(2 + x)^{6}$ , in ascending power of x are,

$64 , 192 \times x^{1} {\textrm{ and }}240 \times x^{2}$

coefficient of $x^{2}$ in the expansion of $(2+x - x^{2})^{6}$ = (240 - 192) = 48

Step-by-step explanation:

$(2+x)^{6}$

= $\sum_{k=0}^{6}(6_{C_{k}} \times x^{k} \times 2^{6 - k})$

= $6_{C_{0}} \times x^{0} \times 2^{6} + 6_{C_{1}} \times x^{1} \times 2^{5} + 6_{C_{2}} \times x^{2} \times 2^{4}$ + terms involving higher powers of x

= $64 + 192 \times x^{1} + 240 \times x^{2}$ + terms involving higher powers of x

so, the first 3 terms in the expansion of $(2 + x)^{6}$ , in ascending power of x are,

$64 , 192 \times x^{1} {\textrm{ and }}240 \times x^{2}$

Again,

$(2+x - x^{2})^{6}$

= $\sum_{k=0}^{6}(6_{C_{k}} \times (2 + x)^{k} \times (-x^{2})^{6 - k})$

Now, by inspection,

the term $x^{2}$ comes from k =5 and k = 6

for k = 5, the coefficient of $x^{2}$ is , $(-32) \times 6$ = -192

for k = 6 , the coefficient of $x^{2}$ is, $6_{C_{2}} \times 2^{4}$ = 240

so, coefficient of $x^{2}$ in the final expression = (240 - 192) = 48

3 0

2 years ago