The answer is "quadrant II" because first u go five left because of the negative five which is on the x axis then go up 10 because of the positive 10 which on the y axis
I need more information for help you answer this
Split up the interval [0, 2] into <em>n</em> equally spaced subintervals:
![\left[0,\dfrac2n\right],\left[\dfrac2n,\dfrac4n\right],\left[\dfrac4n,\dfrac6n\right],\ldots,\left[\dfrac{2(n-1)}n,2\right]](https://tex.z-dn.net/?f=%5Cleft%5B0%2C%5Cdfrac2n%5Cright%5D%2C%5Cleft%5B%5Cdfrac2n%2C%5Cdfrac4n%5Cright%5D%2C%5Cleft%5B%5Cdfrac4n%2C%5Cdfrac6n%5Cright%5D%2C%5Cldots%2C%5Cleft%5B%5Cdfrac%7B2%28n-1%29%7Dn%2C2%5Cright%5D)
Let's use the right endpoints as our sampling points; they are given by the arithmetic sequence,
where 
. Each interval has length 
.
At these sampling points, the function takes on values of
We approximate the integral with the Riemann sum:
Recall that
so that the sum reduces to
Take the limit as <em>n</em> approaches infinity, and the Riemann sum converges to the value of the integral:
Just to check:
The answer is a rational number is one integer divided by
another, and can be represented in either decimal of fraction form. The explanation
behind this is visualize you are using long division to divide one number by one
more. You divide, and then you acquire a remainder. Then you carry down a
zero (multiply by ten) and divide again. Well, there are only so many balances
you could perhaps have. For example, for 5, your choices are 0, 1, 2, 3,
and 4. Sooner or later, you will replicate a remainder, at which fact you
will just keep dividing the same method you did last time you saw that
remainder -- and that's the reason why it repeats.
N+n+2+n+4=54
3n+6=54
3n=48
n=16
16, 18, 20
