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Given:
A line through the points (7,1,-5) and (3,4,-2).
To find:
The parametric equations of the line.
Solution:
Direction vector for the points (7,1,-5) and (3,4,-2) is
Now, the perimetric equations for initial point with direction vector
, are
The initial point is (7,1,-5) and direction vector is . So the perimetric equations are
Similarly,
Therefore, the required perimetric equations are and
.
Answer:
= 8
= 6
Therefore the co-ordinate of the center of mass is =
Step-by-step explanation:
Center of mass: Center of mass of an object is a point on the object. Center of mass is the average position of the system.
Center of mass of a triangle is the centriod of a triangle.
Given that m₁= 4, m₂=3, m₃=3 and the points are P₁(2,-3), P₂(-3,1) and P₃(3,5)
= ∑(mass × x-co-ordinate)
= ∑(mass × y-co-ordinate)
Therefore
= (4×2)+{3×(-3)}+(3×3)
=8
= {4×(-3)}+{3×1}+(3×5)
=6
The x co-ordinate of the center of mass is the ratio of to the total mass.
The y co-ordinate of the center of mass is the ratio of to the total mass.
Total mass (m) = m₁+ m₂+ m₃
= 4+3+3
=10
The x co-ordinate of the center of mass is
The y co-ordinate of the center of mass is
Therefore the co-ordinate of the center of mass is =