Helpp please will mark brainlest

Mathematics

2 answers:

hram777 [196]2 years ago

8 0

Answer:

what do you need help with?

Step-by-step explanation:

tia_tia [17]2 years ago

8 0

Answer:

I will try to help you on the other question you posted. The one with the picture.

Step-by-step explanation:

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What is the total change in the number of cups in oatmeal container? Explain.

yanalaym [24]

Answer:

There is not enough information to answer this question

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

Find a linear second-order differential equation f(x, y, y', y'') = 0 for which y = c1x + c2x3 is a two-parameter family of solu

Alisiya [41]

Let $y=C_1x+C_2x^3=C_1y_1+C_2y_2$ . Then $y_1$ and $y_2$ are two fundamental, linearly independent solution that satisfy

$f(x,y_1,{y_1}',{y_1}'')=0$
$f(x,y_2,{y_2}',{y_2}'')=0$

Note that ${y_1}'=1$ , so that $x{y_1}'-y_1=0$ . Adding $y''$ doesn't change this, since ${y_1}''=0$ .

So if we suppose

$f(x,y,y',y'')=y''+xy'-y=0$

then substituting $y=y_2$ would give

$6x+x(3x^2)-x^3=6x+2x^3\neq0$

To make sure everything cancels out, multiply the second degree term by $-\dfrac{x^2}3$ , so that

$f(x,y,y',y'')=-\dfrac{x^2}3y''+xy'-y$

Then if $y=y_1+y_2$ , we get

$-\dfrac{x^2}3(0+6x)+x(1+3x^2)-(x+x^3)=-2x^3+x+3x^3-x-x^3=0$

as desired. So one possible ODE would be

$-\dfrac{x^2}3y''+xy'-y=0\iff x^2y''-3xy'+3y=0$

(See "Euler-Cauchy equation" for more info)

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3 years ago

Triangle P Q R is shown. The length of P Q is 20 and the length of P R is 12. Angle Q P R is 68 degrees and angle P Q R is 36 de

Tom [10]

Answer:

<h2> 112.3 square units</h2>

Step-by-step explanation:

Find the sketch of the triangle attached.

Area of the triangle = $\frac{1}{2}|PQ| |PR| sinQPR$