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skelet666 [1.2K]
3 years ago
5

Please I need help with this question

Mathematics
2 answers:
Karo-lina-s [1.5K]3 years ago
8 0

Answer:

The answer is option A.

<em><u>Hope</u></em><em><u> </u></em><em><u>it helps</u></em><em><u>.</u></em><em><u>.</u></em>

olchik [2.2K]3 years ago
5 0

Answer:

Step-by-step explanation:

2/3(6y + 9)

2/3(6y) = 4y

2/3(9) = 6

=4y + 6 (A)

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John’s father is 5 times older than John and John is twice as old as his sister Alice. In two years time, the sum of their ages
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Answer:

8 years

Step-by-step explanation:

Let age of father be f

age of John be j

age of Alice be a

John's father is 5 times as old as John. We can write:

f = 5j

John is twice as old as Alice. We can write:

j = 2a

or

a = j/2

SUM OF ALL OF THEIR AGES (after 2 years) will be 58. We can write:

f+2 + j+2 + a+2 = 58

This becomes:

f + j + a + 6 = 58

f + j + a = 52

Now, we replace third equation with the first two (in bold) and get:

f + j + a = 52\\5j + j + \frac{1}{2}j=52\\6.5j=52\\j=8

So John is 8 years old

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Two triangles can be formed with the given information. Use the Law of Sines to solve the triangles. C = 71°, a = 27, c = 26
guajiro [1.7K]

We have

SinC/ c  = Sin A / a

Sin 71/ 26 = Sin A / 27

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So°

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b = 26sin29.92/sin71 =  about 13.72

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So we have

B = 180 - 71 - 100.92 = 8.08°

And we have

b / sin 8.08  = 26/sin71

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Step-by-step explanation:

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