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Advocard [28]
3 years ago
13

Find the area of each regular polygon. Round your answer to the nearest tenth. Show your work.

Mathematics
2 answers:
Virty [35]3 years ago
6 0
I'm too lazy to show your work but here are the answers:

a) approx. 120.71 in^2
b) approx. 86.603 in^2 (if 5 = INRADIUS)
    approx. 64.952 in^2 (if 5 = CIRCUMRADIUS)

Plenty of sources and calculators online
Helen [10]3 years ago
3 0
See picture for answers

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PLEASEEEEE i don’t get it I know it’s easy i will give you the brainlest!
Vika [28.1K]

Answer:

h=2/ab

Step-by-step explanation:

4 0
3 years ago
Solve using a suitable inverse operation:
Olenka [21]

Answer:

a = - 10

Step-by-step explanation:

Given

\frac{a}{5} = - 2

a is divided by 2. The inverse operation to division is multiplication, thus

Multiply both sides by 5 to clear the fraction

a = 5 × - 2 = - 10

7 0
3 years ago
H(x) = {(3,-5), (5.-7), (6,-9), (10, -12), (12,1-16)}<br> Which of the following gives h^-1(x)
Lemur [1.5K]

Answer:

its b

Step-by-step explanation:

because each pair is inversed

7 0
3 years ago
8. If k = log, 3 then log, 48 =<br> 16<br> (1) 2k +3<br> (3) k +8<br> (2) 3k +1<br> (4) k +4
vekshin1

assuming you means k = log_2(3) [as log(2)3 is the same thing as 3log(2) due to multiplication being commutative]

given log(ab) = log(a) + log(b)

log_2(48) = log_2(3) + log_2(16)

5 0
3 years ago
You are in a hot air balloon looking down at two ponds. Pond A which is in front of your balloon, is at an angle of depression t
MatroZZZ [7]

a. See attachment for the labelled diagram

b. Using the sine ratio, distance from the hot air to pond A is 5,038.9 m, while distance from the hot air to pond B is 6,287.1 m.

c. Distance between the two ponds is 1,263.5 m.

<h3>What is the Sine and Tangent Ratios?</h3>

Sine ratio, is: sin ∅ = opposite side/hypotenuse length

Tangent ratio is: tan ∅ = opposite side/adjacent length.

a. The diagram with the appropriate labels is shown in the image attached below.

b. Use the sine ratio to find the distance from the hot air to pond A (CA) and to pond B (CB):

CA = hypotenuse

∅ = 10°

Opposite = 875 m

sin 10 = 875/CA

CA = 875/sin 10

CA ≈ 5,038.9 m (distance from the hot air to pond A)

CB = hypotenuse

∅ = 8°

Opposite = 875 m

sin 8 = 875/CB

CB = 875/sin 8

CB ≈ 6,287.1 m (distance from the hot air to pond B)

c. Distance between the two ponds, BA = BD + DA.

Apply the tangent ratio to find BD and DA

tan 8 = 875/BD

BD = 875/tan 8

BD = 6,225.9 m

tan 10 = 875/DA

DA = 875/tan 10

DA = 4,962.4 m

Distance between the two ponds = 6,225.9 - 4,962.4 = 1,263.5 m.

Learn more about the sine and tangent ratios on:

brainly.com/question/24137232

#SPJ1

8 0
2 years ago
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