The amount of strontium that will remain after 40 hours is 5 g
<h3>How to determine the number of half-lives </h3>
- Half-life (t½) = 10 hours
- Time (t) = 40 hours
- Number of half-lives (n) =?
n = t / t½
n = 40 / 10
n = 4
<h3>How to determine the amount remaining </h3>
- Original amount (N₀) = 80 g
- Number of half-lives (n) = 4
N = N₀ / 2ⁿ
N = 80 / 2⁴
N = 80 / 16
N = 5 g
Learn more about half life:
brainly.com/question/26374513
The probability that the manufacturing unit has carbon emissions beyond the permissible emission level is 0.2975
Given that the probability that carbon emissions from the company’s factory exceed the permissible level is 35% and the accuracy of the test is 85%.
The possibility of an event or outcome happening contingent on the occurrence of a prior event or outcome is known as conditional probability. The probability of the prior event is multiplied by the current likelihood of the subsequent, or conditional, occurrence to determine the conditional probability.
Event A: The given Carbon emission beyond to the given permissible emission level.
Event B: Test predicts this.
To get the probability of this problem, first we need to divide by 100 the given values.
A=35/100
A=0.35
The probability of event A is P(A)=0.35
And the probability is P(B|A)=85/100=0.85
Now, we will use the conditional probability formula, we get
P(B|A)=P(A∩B)/P(A)
0.85=P(A∩B)/0.35
P(A∩B)=0.85×0.35
P(A∩B)=0.2975
Hence, the probability that the manufacturing unit has carbon emissions beyond the permissible emission level and the test predicts is0.2975.
Learn more about conditional probability from here brainly.com/question/12985746
#SPJ4
The answer is C: first add 2 both sides then divide both sides by -5.
In the attached image, I have plotted, in correct spaces.