Answer:

The domain of the inverse of a relation is the same as the range of the original relation. In other words, the y-values of the relation are the x-values of the inverse.
Thus, domain of f(x): x∈R = range of f¯¹(x)
and range of f(x): x∈R =domain of f¯¹(x)
Given:
The system of equations is:
Line A: 
Line B: 
To find:
The solution of given system of equations.
Solution:
We have,
...(i)
...(ii)
Equating (i) and (ii), we get



Divide both sides by 2.

Substituting
in (i), we get
The solution of system of equations is (-4,-8).
Now verify the solution by substituting
in the given equations.


This statement is true.
Similarly,



This statement is also true.
Therefore, (-4,-8) is a solution of the given system of equations, because the point satisfies both equations. Hence, the correct option is C.
Answer:
3/2 or 1 1/2
Step-by-step explanation:
5÷3 1/3
5/1 ÷ 10/3 because you have to get it into an improper fraction form in order to divide
5/1 × 3/10 because you have to multiply the first number by the reciprocal
5 and 10 cancel out so you would have 2 at the bottom
3/2 or 1 1/2
Answer:
Two consecutive integers are of the form
x and x + 1
Their product is equal to 56
x(x + 1) = 56
Solve and find the two numbers x and x + 1. The above equation may be written as follows
x2 + x - 56 = 0
Factor and solve
(x - 7)(x + 8) = 0
solutions: x = 7 , x = -8
x= - 8 is not valid since the number sought must be positive. Hence
x = 7 and x + 1 = 8 are the two consecutive numbers.
Step-by-step explanation: