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1 year ago

Which term best describes the expression 3x2y4 + 5x + 1?

Mathematics

1 answer:

notka56 [123]1 year ago

5 0

Answer:

Trinomial.

Step-by-step explanation:

Note how much terms there are in the given expressions:

Term 1: $3x^{2}y^{4}\$

Term 2: $5x$

Term 3: $1$

Note each meaning of the terms:

Monomial: Having only one term.

Binomial: Having two terms.

Trinomial: Having three terms.

Polynomial: Typically used to describe expressions with 4 or more terms.

In this case, there are only 3 terms, and so your answer is Trinomial.

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(6+3)+21=6+(3+21) name each property of addition or multiplication

Anna007 [38]

(6 + 3) + 21 = 6 + (3 + 21)

It's an ASSOCIATIVE PROPERTY
(a + b) + c = a + (b + c)

7 0

3 years ago

Let f(x)=g(x)h(x), g(10)=-4, h(10)=560, g'(10)=0, and h'(10)=35. find f'(10)

Ulleksa [173]

This question has extraneous info to trick you.
f(x) = g(x)h(x) ⇒ f'(x) = g'(x)h'(x) . Letting x = 10, we get f'(10) = g'(10)h'(10). then just plug in the values provided. g(10) and h(10) are there to throw you off, just use g'(10) and h'(10).
So f'(10), pronounced "eff prime of ten", = 0 * 35 = 0.

If the question were asking for f(10) instead of f'(10) then you would use g(10) and h(10), ⇒-4*560=90.

7 0

3 years ago

Can someone explain how to get the answer for the following question ?

zhenek [66]

The answer to the question is 1-5

3 0

2 years ago

On Mars the acceleration due to gravity is 12 ft/sec^2. (On Earth, gravity is much stronger at 32 ft/sec^2.) In the movie, John

insens350 [35]

Solution :

Given initial velocity, v= 48 ft/s

Acceleration due to gravity, g = $12\ ft/s^2$

a). Therefore the maximum height he can jump on Mars is

$H_{max}=\frac{v^2}{2g}$

$H_{max} = \frac{(48)^2}{2 \times 12}$

= 96 ft

b). Time he can stay in the air before hitting the ground is

$T=\frac{2v}{g}$

$T=\frac{2 \times 48}{12}$

= 8 seconds

c). Considering upward motion as positive direction.

v = u + at

We find the time taken to reach the maximum height by taking v = 0.

v = u + at

0 = 16 + (12) t

$t=\frac{16}{12}$

$=\frac{4}{3} \ s$

We know that, $S=ut + \frac{1}{2}at^2$

Taking t = $=\frac{4}{3} \ s$ , we get

$S=16 \times\frac{4}{3} + \frac{1}{2}\times(-12) \times \left(\frac{4}{3}\right)^2$

$S=\frac{32}{3}$ feet

Thus he can't reach to 100 ft as it is shown in the movie.

d). For any jump whose final landing position will be same of the take off level, the final velocity will be the initial velocity.

Therefore final velocity is = -16 ft/s

3 0

2 years ago

I need help solving a system of linear equation, and it says to solve it by Substitution.

olga_2 [115]

2x - 3y = -24
x+ 6y = 18

you solve the first one by the x:

2x = -24 + 3y

x = (-24+3y)/2

then you substitute what you found in the other equation and you solve by y

(-24+3y)/2 + 6y = 18 multiply everything by 2

-24 + 3y + 12y = 36

3y + 12y = 36 + 24

15y = 60

y = 60/15

y = 4

Good job! You found your y! :D

Now let's substitute the y in the first equation with 4:

2x - 3(4) = -24

2x - 12 = -24

2x = -24 + 12

2x = -12

x = -12/2

x= -6

Done!! ;) <span />

6 0

2 years ago

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