1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
zloy xaker [14]
3 years ago
14

Help please

Mathematics
1 answer:
Nikitich [7]3 years ago
5 0

Answer:

Step-by-step explanation:

There we go :))

You might be interested in
Jackson and Jonah are both swimming. Jackson swims at 1350 meters per hour. Jonah swims at a speed of 1250 millimeters per secon
Vladimir [108]

For this question we will use the following relations.

100 centimeters=1 meter (or 1 centimeter= 0.01 meter)

10 millimeter=1 centimeter (or 1 mm=0.1 cm)

60 minutes = 1 hour (or 1 min=\frac{1}{60} hour)

Now, Jackson's speed is 1350 meters per hour. This can be converted to cm per minute as follows:

\frac{1350 m}{1 h}=\frac{1350\times 100 cm}{60 min}=2250 cm/min...Equation 1

Likewise, Jonah's swim speed in cm/min can be calculated as:

\frac{1250 mm}{1 s}=\frac{1250\times 0.1 cm}{\frac{1}{60}min } =\frac{125\times 60 cm}{1 min}=7500cm/min...Equation 2

As we can see clearly after comparing Equation 1 and Equation 2, Jonah's swim speed of 7500 cm/min is faster than that of Jackson.

Thus, option B is correct.

7 0
3 years ago
Factor –8x3 – 2x2 – 12x – 3 by grouping. what is the resulting expression? (2x2 – 3)(4x 1) (–2x2 – 3)(–4x 1) (2x2 – 3)(–4x 1) (–
myrzilka [38]

The factors of the expression are \rm (4x+1)(-2x^2-3)

<h3>How to find factors in the expression?</h3>

First group the first two terms and the last two terms together respectively.

The factors of the expression are given by;

\rm -8x^3 -2x^2 - 12x - 3\\\\-2x^2(4x+1)-3(4x+1)\\\\(4x+1)(-2x^2-3)

Hence, the factors of the expression are \rm (4x+1)(-2x^2-3).

To know more about factors click the link given below.

brainly.com/question/9645056

5 0
2 years ago
Read 2 more answers
For Exercises 19-24, a, b, c, and d are distinct lines in the same plane. For each combination of relationships, tell how a and
Olegator [25]

Answer:

a is parallel to d

a and d are parallel, and are perpendicular to c and d (those are parallel to each other)

RESULT

They are parallel

Step-by-step explanation:

5 0
3 years ago
Por favor alguien sabe cuál es. soy un número de 5 dígitos. Mi dígito de las decenas es la suma de mi cientos dígitos y miles de
mixas84 [53]

<span>47184. 
</span>
<span>Así que la suma de los cientos y miles será dos veces el dígito de las unidades . Miles ( 7 ) + cientos ( 1 ) = 8. 8 es dos veces más que el dígito de las unidades ( 4) de los miles de diez dígitos es el mismo que el de un dígito es así, esto hace que los miles a decenas 4 también .
</span>
(No escribo bien en espanol pero te lo traslatide jaja. dame un messaje si no todavia no entiendes) 
5 0
3 years ago
Help anyone can help me do this question 3,I will mark brainlest.​
Arisa [49]

Answer:

a.20 people take both types of drink.

b.22 people drink milk only..

8 0
3 years ago
Other questions:
  • How do you solve this?
    9·2 answers
  • Tina had $47.10 in her bank account on Monday. She withdrew $25 on Monday and also made a deposit of an amount d that she cannot
    6·1 answer
  • Two armadillos and three aardvarks sat in a five-seat row at the Animal Auditorium. What is the probability that the two animals
    6·1 answer
  • HELP PLEASE<br> If anyone can help I’m panicking
    5·2 answers
  • Can someone help me on 6?
    7·2 answers
  • Please help me. and thanks
    7·2 answers
  • Is it possible for somebody to help me with a worksheet I will do that Brainly thing please
    11·1 answer
  • Factor the expression completely. 10x^5 -7×^3?​
    10·2 answers
  • Confused!! The picture below shows the question.
    5·1 answer
  • How much cost Rs 1136 when it is 10% discount and 13% vat is added then find out the discount and Vat amount
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!