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Katen [24]
1 year ago
12

In the diagram, the circle will be dilated by a scale factor of 3 about the origin. The points C, A, and B map to C', A', and B'

after the dilation. What is the length of ? Use the distance formula to help you decide: . A. 5 units B. 15 units C. 21 units D. 24 units E. 45 units
Mathematics
2 answers:
Elis [28]1 year ago
8 0
The answer is C
-Hope it helps!
……….
IgorC [24]1 year ago
7 0

Answer:C is the answer

Step-by-step explanation:

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What is 7a +6c+9a-15c
jeka94

                               7a + 6c + 9a - 15c

-- Look for all the 'a's      7a,  9a

-- Addum up                    16a

-- Look for all the 'c's      6c,  -15c

-- Addum up                     -9c

-- Write the results         16a - 9c
3 0
3 years ago
Read 2 more answers
What is the slope of (10, 4), (4, 15)?
kakasveta [241]

Answer:

Slope is -11/6

Step-by-step explanation:

Given \:   points \:   are \:    (10,4) \:  \: and \: (4,15) \\ slope \:  =  \frac{y2 - y1}{x2 - x1}  \\ here \: x1 = 10 \:  \:  \: y1 = 4 \\ and \:  \: x2 = 4 \:  \:  \: and \:  \: y2 = 15 \\ on \: substituting \: the \: values \: in \: formula \\ slope =  \frac{15 - 4}{4 - 10}  \\  =  \frac{11}{ - 6}

<em>HAVE A NICE DAY</em><em>!</em>

<em>THANKS FOR GIVING ME THE OPPORTUNITY</em><em> </em><em>TO ANSWER YOUR QUESTION</em><em>.</em>

6 0
2 years ago
I need help with these 2 questions!! please 20 points!!!
bezimeni [28]

9514 1404 393

Answer:

  1. 45 cm²
  2. 38 cm²

Step-by-step explanation:

The conventional way to work these problems is to make use of the formulas for areas of a triangle, rectangle, and semicircle. If you've used these formulas for a while, you recognize that they give you certain relationships that may make these problems easy to do mentally.

__

1. The area of a triangle is half the product of height and width, so is equivalent to the area of a rectangle either half as high, or half as wide. We note that the width of the sail is 5 cm, so half that is 2.5 cm--exactly the same as the height of the boat's hull. That means we can add the height of the sail to the length of the boat, and the total area can be considered to be the same as that of a rectangle that is

  2.5 cm high × (12 cm + 6 cm) long = (2.5)(18) cm² = 45 cm²

__

2. The usual formula for the area of a circle is ...

  A = πr²

When expressed in terms of diameter, this becomes ...

  A = π(d/2)² = (π/4)d²

Then the area of a semicircle is half that, or (π/8)d². This is equivalent to the area of a rectangle that is "d" wide and "π/8·d" high. That is, the approximate area of the semicircle is that of a rectangle 4 cm high by (π/8·4 cm) = π/2 cm wide. In other words, the semicircle effectively adds π/2 cm to the left end of the 6 cm central rectangle of the figure.

As discussed above, the area of a triangle is equivalent to the area of a rectangle half as high. In this figure, the triangle is 10-6 = 4 cm wide, so can be considered to contribute 4/2 = 2 cm to the right end of the 6 cm central rectangle.

If we consider π ≈ 3, then the approximate area of the figure is ...

  (4 cm)(3/2 cm + 6 cm + 2 cm) = (4)(9.5) cm² = 38 cm²

__

The exact value is 4(8+π/2) = 32+2π ≈ 38.283 cm².

7 0
2 years ago
Three times each day, a quality engineer samples a component from a recently manufactured batch and tests it. Each part is class
Tresset [83]

Answer:

Step-by-step explanation:

Hello!

Three samples of components manufactured are taken per day. They are classified as:

D: "Conforming (suitable for its use)"

E: "Downgraded (unsuitable for the intended purpose but usable for another purpose)"

F: "Scrap (not usable)"

This classification includes the three events that may occur in your sample space S. The experiment consists in recording the categories of the three parts tested in a day.

a. List the 27 outcomes in the sample space.

The possible outcomes in the space sample are the combinations of the three events. To avoid using the same letters as in the following questions I've named the evets as D, E, and F

S={DDD, DED, DFD, DEF, DFE, DEE, DFF, DDE, DDF , EDE, EEE, EFE, EED, EEF, EDF, EFD, EDD, EFF , FDF, FEF, FFF, FFE, FFD, FDE, FED, FDD, FEE}

b. Let A be the event that all the parts fall into the same category. List the outcomes in A.

A: "All the parts fall into the same category"

You have three possible outcomes for this event, that the three compounds are conforming, "DDD", that the three are unconforming, "EEE", or that the three compounds are scrap, "FFF". There are only three possible outcomes for this event.

S={DDD, EEE, FFF}

c. Let B be the event that there is one part in each category. List the outcomes in B.

B: "There is a part in each category"

This means, for example, The first one is conforming "D", the second one is unconforming "E" and the third one is scrap "F", then the first one may be unconforming "E", the second one is conforming "D" and the thirds one is scrap "F", and so on, you have 6 possible outcomes for this event:

S={DEF, DFE, EDF, EFD, FDE, FED}

d. Let C be the event that at least two parts are conforming. List the outcomes in C.

C: "At least two parts are conforming"

For this event, you can have two of the compounds to be considered conforming or the three of them.

S={DDD, DED, DFD, DDE, DDF , EDD, FDD}

A total of 7 combinations fit this event.

I hope you have a SUPER day!

6 0
2 years ago
Math with Exponents
sergey [27]
Example

2^3 4^2
2×2×2=6 4×4=16

All you do is multiply the number by the exponent however many times the exponents is
7 0
3 years ago
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