Given:
The system of equations is


To find:
The missing value for which the given system of equations have infinitely many solutions.
Solution:
Let the missing value be k.
We have,


Taking all the terms on the left side, the given equations can be rewritten as


The system of equations
and
have infinitely many solutions if

We have,


Now,



On cross multiplication, we get


Therefore, the missing value is -10.
Answer:
1. X= 4
2. X= 1
3. X= 3
4. X= 5
5. X= 7
6. X= -3/4
7. X= 6
8. X= 5
Step-by-step explanation:
A. Thay intersect at one point.
Answer:
8 years
Step-by-step explanation:
Let age of father be f
age of John be j
age of Alice be a
John's father is 5 times as old as John. We can write:
f = 5j
John is twice as old as Alice. We can write:
j = 2a
or
a = j/2
SUM OF ALL OF THEIR AGES (after 2 years) will be 58. We can write:
f+2 + j+2 + a+2 = 58
This becomes:
f + j + a + 6 = 58
f + j + a = 52
Now, we replace third equation with the first two (in bold) and get:

So John is 8 years old
Answer:
z=-60
Step-by-step explanation:
1/6z=-10
z=-10×6
z=-60