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lesya [120]
3 years ago
7

What is the answer for this one?

Mathematics
1 answer:
pshichka [43]3 years ago
3 0
<h2>1. Find the SA of all of the parts:</h2>

SA of Triangle parts:

We won't be doing 5x6x1/2 because if we want the surface area of 2 areas, then we will just do normal (5x6)

(2 × 8 2) + (3 × 10 2)

SA: B x H

    : 5 x 6

    : 30

The surface area of the triangular parts is 30cm²

SA of Large Rectangular (in the middle) part:

SA: L x W

    : 6 x 16

    : 96

The surface area of the rectangular parts is 96cm²

SA of Large Rectangular (top&bottom) part:

SA: L x W x 2

    : 16 x 8 x 2

    : 256

The surface area of the rectangular parts is 256cm²

<h2>2. Add all the SA's to get FINAL answer:</h2>

30+96+256=382

<h2>So hence, The SA of the Triangular prism is: 382cm²</h2>

:D

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Answer:

50

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the fifth number is 50.

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3 years ago
What is 4/9÷2/3 show work please!
alexira [117]
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First, apply the rule: a ÷ \frac{b}{c} = a × \frac{c}{b}
\frac{4}{9} × \frac{3}{2}
Second, apply the rule: \frac{a}{b} × \frac{c}{d} = \frac{ac}{bd}
\frac{4x3}{9x2}
Third, multiply 4 × 3 to get 12, and 9 × 2 to get 18.
\frac{12}{18}
Fourth, find the GCF of 12 and 18.
Factors of 12: 1, 2, 3, 4, 6, 12
Factors of 18: 1, 2, 3, 6, 9, 18
The GCF is 6.
Fifth, divide the numerator by the GCF. 
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Sixth, divide the denominator by the GCF. 
18 ÷ 6 = 3
Seventh, rewrite your fraction.
\frac{2}{3}

Answer as fraction: \frac{2}{3}
Answer as decimal: 0.6667

7 0
3 years ago
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A TRIANGLE HAS SIDES WITH LENGTHS OF 4 meters, 5 meters,AND 7 meters.
Leviafan [203]

Answer:

I believe the answer is no

Step-by-step explanation:

Because they are all different numbers

3 0
3 years ago
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Virgil has 1/6 of a birthday cake left over. He wants to share the leftover cake with 3 friends. What fraction of the original c
FromTheMoon [43]
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3 0
3 years ago
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If csc 0=8÷7 which equation represents cot 0
Dahasolnce [82]

Answer: Cot\theta =\frac{\sqrt{15} }{7}

Step-by-step explanation:

Since, given cosec\theta=\frac{8 }{7}

And we know that Cot\theta=\sqrt{cosec^2\theta-1}

Therefore, Cot\theta=\sqrt{cosec^2\theta-1} = \sqrt{(8/7)^2-1}= \sqrt{64/49-1}

⇒Cot\theta=\sqrt{64-49/49}=\sqrt{15/49}=\sqrt{15}/7

Thus,  Cot\theta =\frac{\sqrt{15} }{7}


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