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lesya [120]
3 years ago
7

What is the answer for this one?

Mathematics
1 answer:
pshichka [43]3 years ago
3 0
<h2>1. Find the SA of all of the parts:</h2>

SA of Triangle parts:

We won't be doing 5x6x1/2 because if we want the surface area of 2 areas, then we will just do normal (5x6)

(2 × 8 2) + (3 × 10 2)

SA: B x H

    : 5 x 6

    : 30

The surface area of the triangular parts is 30cm²

SA of Large Rectangular (in the middle) part:

SA: L x W

    : 6 x 16

    : 96

The surface area of the rectangular parts is 96cm²

SA of Large Rectangular (top&bottom) part:

SA: L x W x 2

    : 16 x 8 x 2

    : 256

The surface area of the rectangular parts is 256cm²

<h2>2. Add all the SA's to get FINAL answer:</h2>

30+96+256=382

<h2>So hence, The SA of the Triangular prism is: 382cm²</h2>

:D

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Area is a squared number.  We know that from the label we use when we solve problems involving area.  Perimeter is a single unit label.  This single unit label can also be used to find scale factor, since single unit labels are one-to-one.  If the area of polygon F is 36, that means that the single unit measure was a number that was squared to get to the area.  Same goes for polygon G.  That means that in order to find the single unit measure of each of those we have to take the square root of the area.  The square root of 36 is 6, and the square root of 4 is 2.  6:2 is the scale factor, but that can be reduced to 3:1, larger to smaller.

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4 years ago
Which statement are true
Ket [755]

Answer:

  • Line XY contains ray OX and ray OY
  • Line XY contains segment YX
  • Ray YX exists in the diagram

Step-by-step explanation:

A ray can be named by any pair of points on an infinite line. Point O, X, and Y on the same line can be used to name rays OX, OY, XY, YX, OY, and XO. The first point named is the end point of the ray. The ray goes through the other point and continues indefinitely.

BA can be the name of a line segment, but not a ray. The line shown does not extend from point B beyond point A.

Any segment can be named by its end points in either order.

So, we have ...

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