Answer:
Step-by-step explanation:
Given :The sum of three times a number and 6 is at least 12.
To Find:Write an inequality for the given statement
Solution:
Let n be the number
So, 3 times of a number = 3n
Now Sum of three times of a number and 6 = 3n+6
Since we are given that the sum of three times a number and 6 is at least 12(i.e. equal to or greater than 12)
So, A.T.Q.
Thus an inequality for the given statement: the sum of three times a number and 6 is at least 12 is
4x+2y=200
B.
(f-g)(x) = f(x) - g(x) =
= (3x³ + 8x² -7x - 4) - (2x - 6) = 3x³ + 8x² - 7x - 4 - 2x + 6 =
= 3x³ + 8x² - 9x + 2
20
just divide 600 by 30
your answer is for sure please see the solution