Could you guys help me solve 9 I would appreciate it :)
1 answer:
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Answer:
a) Sample correlation coefficient, r = 0.7411
bi) test statistic, t = 4.102
bii) P-value = 0.000736
Step-by-step explanation:
a) The formula for the sample correlation coefficient is given by the formula:
r = 0.7511
b)
i) formula for the test statistic is given by the formula:
sample size, n = 4
t = 4.102
ii) Degree of freedom, df = n -2
df = 14 -2
df = 12
The P-value is calculate from the degree of freedom and the test statistic using excel
P-value =(=TDIST(t,df,tail))
P-value = (=TDIST(4.1,12,1)
P-value = 0.000736