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ExtremeBDS [4]
3 years ago
12

Could you guys help me solve 9 I would appreciate it :)

Mathematics
1 answer:
Drupady [299]3 years ago
5 0

Answer:

Step-by-step explanation:

12<18/3(-2)+12  turns into 12<18/-6+12

False

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Describe the differences between angles in right triangles and angles of rotation.
fomenos

Answer:

Angles in right triangles must have measures between 0 and 90°. Angles of rotation can be any real number, which includes negative as well as positive values.

Step-by-step explanation:

Answer on E2020

7 0
3 years ago
The table below shows how much Joe earns, y, after working x hours.
FromTheMoon [43]

Answer: Given : Joe’s Earnings and hour worked

The relationship between money earned and hours worked is linear.

Joe computes the slope between (4, 30) and (12, 90), then computes the slope between (4, 30) and (10, 75).

To Find : How do the two slopes compare?

Solution:

Hours worked     Money earned

4                          $30

10                        $75

12                        $90

22                       $165

slope between (4, 30) and (12, 90),

= (90 - 30)/(12 - 4)

= 60/8

= 15/2

slope between (4, 30) and (10, 75)

= (75 - 30)/(10-4)

= 45/6

= 15/2

The slope between (4, 30) and (12, 90) and between (4, 30) and (10, 75) is the same.

Both Slopes are same.

i hope this helped and have a nice day/night

4 0
3 years ago
. Use the quadratic formula to solve each quadratic real equation. Round
Liono4ka [1.6K]

Answer:

A. No real solution

B. 5 and -1.5

C. 5.5

Step-by-step explanation:

The quadratic formula is:

\begin{array}{*{20}c} {\frac{{ - b \pm \sqrt {b^2 - 4ac} }}{{2a}}} \end{array}, with a being the x² term, b being the x term, and c being the constant.

Let's solve for a.

\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {5^2 - 4\cdot1\cdot11} }}{{2\cdot1}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {25 - 44} }}{{2}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {-19} }}{{2}}} \end{array}

We can't take the square root of a negative number, so A has no real solution.

Let's do B now.

\begin{array}{*{20}c} {\frac{{ 7 \pm \sqrt {7^2 - 4\cdot-2\cdot15} }}{{2\cdot-2}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 7 \pm \sqrt {49 + 120} }}{{-4}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 7 \pm \sqrt {169} }}{{-4}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 7 \pm 13 }}{{-4}}} \end{array}

\frac{7+13}{4} = 5\\\frac{7-13}{4}=-1.5

So B has two solutions of 5 and -1.5.

Now to C!

\begin{array}{*{20}c} {\frac{{ -(-44) \pm \sqrt {-44^2 - 4\cdot4\cdot121} }}{{2\cdot4}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 44 \pm \sqrt {1936 - 1936} }}{{8}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 44 \pm 0}}{{8}}} \end{array}

\frac{44}{8} = 5.5

So c has one solution: 5.5

Hope this helped (and I'm sorry I'm late!)

4 0
3 years ago
Rich makes $12.50 an hour. If Rich works 56 hours in one week, how much would he earn for the week
ICE Princess25 [194]
$700 is your answer.
5 0
3 years ago
Read 2 more answers
Which of the following lines is not parallel to y = - 3x - 7?*
inn [45]
I think the third one
3 0
3 years ago
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