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inysia [295]
3 years ago
6

A box is 1 meter wider than its height and 2 meters longer than his width.

Mathematics
1 answer:
sukhopar [10]3 years ago
6 0

Let the height be x

Hence, the width is $x+1$ and length is $(x+1)+2=x+3$

The volume is given to be 2 m³

Hence, $2=x(x+1)(x+3)$

Solving,

$x^3+4x^2+3x-2=0$

$(x+2)(x^2+2x-1)=0$

$\implies x+2=0$ or $x^2+2x-1=0$

But $x=-2$ cannot be possible

Hence, $x^2+2x-1=0$

$\implies x=-1-\sqrt 2$ or $x=-1+\sqrt 2$

Reject the negative solution.

Hence, the height is $\sqrt 2-1$,

width is $\sqrt 2$ and length is $\sqrt 2 +2$

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The numbers of pages in the books in a library follow a normal distribution. If the mean num
bogdanovich [222]

Answer:

For the answer to the question above, the numbers of pages in the books in a library follow a normal distribution. If the mean number of pages is 180 and the standard deviation is 30 pages, you can conclude that about 16% of the books have fewer than 150 pages.

7 0
2 years ago
BRAINIEST TO WHOEVER RIGHT
Anna35 [415]

Could you get a closer picture?

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2 years ago
Plzzzzz answer this question about density mass and volume!!!!!!!!!
nataly862011 [7]

Answer:

13.896 kg

Step-by-step explanation:

You can find the mass of the bar by first finding the volume.

V = BH

where B = area of the base (the trapezium), and

H = height (distance trapezium between bases)

The area of a trapezium is

A = (b1 + b2)h/2

where b1 and b2 are the lengths of the bases of the trapezium (the parallel sides), and

h = the altitude of the trapezium (distance between the bases of the trapezium)

V = (b1 + b2)h/2 * H

V = (12 cm + 6 cm)(5 cm)/2 * 16 cm

V = 720 cm^3

The volume of the bar is 720 cm^3.

Now we use the density and the volume to find the mass.

density = mass/volume

mass = density * volume

mass = 19.3 g/cm^3 * 720 cm^3

mass = 13,896 g

Now we convert grams into kilograms.

1 kg = 1000 g

mass = 13,896 g * (1 kg)/(1000 g)

mass = 13.896 kg

Answer: 1.3896 kg

6 0
3 years ago
Please help me please will give brainliest to anyone <br><br><br><br><br>only do number 11​
AnnZ [28]

9514 1404 393

Answer:

  9.  ±1, ±2, ±3, ±6

  11.  ±1, ±2, ±3, ±4, ±6, ±12

Step-by-step explanation:

The possible rational roots are (plus or minus) the divisors of the constant term, divided by the divisors of the leading coefficient.

Here, the leading coefficient is 1 in each case, so the possible rational roots are plus or minus a divisor of the constant term.

__

9. The constant is -6. Divisors of 6 are 1, 2, 3, 6. The possible rational roots are ...

  ±{1, 2, 3, 6}

__

11. The constant is 12. Divisors of 12 are 1, 2, 3, 4, 6, 12. The possible rational roots are ...

  ±{1, 2, 3, 4, 6, 12}

_____

A graphing calculator is useful for seeing if any of these values actually are roots of the equation. (The 4th-degree equation will have 2 complex roots.)

8 0
3 years ago
Edmundo used a number line to show the solution for the inequality |2x-6|&lt;4 Which number line shows the solution? HURRY PLEAS
Law Incorporation [45]
Break into 2 equatins to get x's:

2x-6<4 and 2x-6>-4

Solve for x in both:

2x-6<4
2x<10
x<5

2x-6>-4
2x>2
x>1

Graph both inequalities on the same number line:

<---0-----1-----2-----3-----4-----5-----6--->
6 0
3 years ago
Read 2 more answers
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